The equation we are looking at would have to be divided by 2 first.
x²-6x+3
When looking at that, I can tell that 1 may be the possible answer since you would have to subtract 6 from both sides. That would leave a 3. Let's check.
(x-3)(x-3)
x²-6x+9=6
Now subtract 6 from both sides.
x²-6x+3=0
So, 1- (x-3)²=6 would be used.
I: 12x-5y=0
II:(x+12)^2+(y-5)^2=169
with I:
12x=5y
x=(5/12)y
-> substitute x in II:
((5/12)y+12)^2+(y-5)^2=169
(25/144)y^2+10y+144+y^2-10y+25=169
(25/144)y^2+y^2+10y-10y+144+25=169
(25/144)y^2+y^2+144+25=169
(25/144)y^2+y^2+169=169
(25/144)y^2+y^2=0
y^2=0
y=0
insert into I:
12x=0
x=0
-> only intersection is at (0,0) = option B
Solve 112 divided by 7 to find the number of muffins in each batch.
The polynomial is the expansion of (x-3)(x-1)(x+4)²
Answer:
relationship between two variables such that when the value of one variable is high then the value of the other variable is probably low
Step-by-step explanation:
