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Pachacha [2.7K]
2 years ago
14

Where n 5 and r = 2 N!/(n-r)

Mathematics
1 answer:
Karo-lina-s [1.5K]2 years ago
5 0

Answer:

\frac{5 \times 4 \times 3 \times 2 \times 1}{5 - 2}  =  \frac{120}{3 }  = 40

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Solve for d in terms of r
Zarrin [17]

Hello!

Answer:

d=2r

Step-by-step explanation:

Simplify both sides and isolate the variable.

Hope this helps!

5 0
2 years ago
Read 2 more answers
- 3x + 4 and passes through the point (2,5)
Anuta_ua [19.1K]

Answer:

y=(x+13)/3

Step-by-step explanation:

the question is not quite clear, i think u mean y= -3x + 4

then, the slope of the line perpendicular to the given line is m1.m2= -1, hence, -3.m2= -1 m2 = 1/3

y-5=1/3(x-2) y=x/3+13/3 or y=(x+13)/3

6 0
3 years ago
A boat that costs $8550 decreases in value by 12% per year. How much will the boat be worth after 3 years?
erastovalidia [21]
You have to take $8,550 times 0.12 (12%) to find out the number it is being decreased by.
8,550 x 0.12 = 1,026
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$5,472
3 0
3 years ago
F ∝ a If F = 48 when a = 3 find, a when F = 32
LenKa [72]

Answer:

2

Step-by-step explanation:

f = a

48 = 3

32 = x

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<u>x=2</u>

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4 0
3 years ago
On the first day of spring, an entire field of flowering trees blossoms. The population of locusts consuming these flowers rapid
Elza [17]

Answer:

L(t)=7600e^{0.2273t}

Step-by-step explanation:

-The locust population grows by a factor and can therefore be modeled by an exponential function of the form:

P=P_oe^{rt}

Where:

  • P is the population after t days.
  • P_o is the initial population given as 7600
  • r is the rate of growth
  • t is time in days

-Given that the growth is by a factor of 5( equivalent to 500%), the r value will be 5

-The population increases by a factor of 5 every 22 days. therefore at any time instance, t will be divided by 22 to get the effective time for calculations.

Hence, the exponential growth function will be expressed as:

P=P_oe^{rt},\ \ \ P=L(t)\\\\\therefore L(t)=7600e^{5\frac{t}{22}}\\\\=7600e^{0.2273t}

7 0
3 years ago
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