Answer:
See Explaination
Explanation:
This assume that input is a file and is given on command line. Please note this will ot print lines with frederick as thats what I feel question is asking for
#!/usr/bin/perl -w
open(FILE, $ARGV[0]) or die("Could not open the file $ARGV[0]");
while ($line = <FILE>){
if($line=~/\s+fred\s+/)
{
print $line;
}
}
close(FILE);
Solution :
Public Function Is a Leap_Year(Year As_Integer) As Integer
'Dim Tor_F for local variable declaring if value is t/f.
Dim TorF As For Boolean
'Pre conditions: Year > 1581 and Year < 3000
If Year > 1581 And Year <> 1700 Or 1800 Or 1900 Then
IsLeapYear = Year / 4
Else
IsLeapYear = False
TorF = False
End If
End Function
<span>The statement that a screentip
is a box with descriptive text about a command that appears when you
point to a button on the ribbon is true. Screentip </span>displays<span><span><span> when you point to icons on the taskbar. The purpose of the screentip is </span> to tell you the name or purpose of the object.</span>
</span>
Answer:
Answer explained below
Explanation:
Yes, you can let Set-uid program that is owned by root to run your code instead of /bin/ls but it has it's own drawbacks and is actually not safe.
As you can not rely on that since some of the shells if different from the ruid drop an euid which is actually not safe.
execl("/bin/ls", "ls",(char *)0);
run this under your main program.
Since it can have a root previlege,
-$ cd /tmp/
/tmp$ sudo su
:/tmp# gcc -o system system.c
:/tmp# chmod u+s system // changing file permissions
:/tmp# exit
exit
:/tmp$ cp /bin/sh /tmp/ls
:/tmp$ ./system
<u>Steps:
</u>
1. The first thing you need to do is copy /bin/sh to /tmp.
2. After copying /bin/sh to /tmp set a new name ls but make sure your sh ->.zsh.
3. Set PATH to current directory. /tmp.
4. Compile
5. Run the program system and you can get your root previledge.
Now, with the above exmaple if you change /bin/sh soo that it points back to /bin/bash and repeat all the previous steps, you will not be able to get your root previledges.
No . A multiuser computer system does not run a network operating system