The best scenario is when a program suffers from frequent
page faults. In the situations when a kernel thread experiences a page fault,
another kernel thread can be switched in; something a single-threaded process
will not be capable of doing. Another best circumstance is when a program has
to wait for other systems events.
Answer:
- def ending_time(hour, minutes, seconds, work_time):
- if((seconds + work_time) // 60 > 0):
- minutes = minutes + (seconds + work_time) // 60
- seconds = (seconds + work_time) % 60
-
- if(minutes // 60 > 0):
- hour = hour + (minutes // 60)
- minutes = minutes % 60
- else:
- seconds = seconds + work_time
-
- return str(hour) + ":" + str(minutes) + ":" + str(seconds)
-
- print(ending_time(2,30,59, 12000))
Explanation:
The solution code is written in Python 3.
Firstly create a function ending_time that takes the four required input parameters.
Next, create an if statement to check if the numerator of (seconds + work_times) divided by 60 is over zero. If so, increment the minute and reassign the remainder of the seconds to the variable (Line 2-4).
Next, create another if statement again to check if the numerator of (current minutes) divided by 60 is over zero, if so increment the hour and reassign the remainder of the minutes to the variable (Line 6-8)
Otherwise, just simply add the work_time to the current seconds
At last return the time output string (Line 12).
Answer:
Don’t know lol but look it up on g00gle and she will have the answr
Explanation:
