Answer:
<h3>6 days</h3>
Step-by-step explanation:
Given the inequality expression of the total cost (c) in dollars of renting a car for n days as c ≥ 125 + 50n
To get the maximum number of days for which a car could be rented if the total cost was $425, substitute c = 425 into the expression and find n
425 ≥ 125 + 50n
Subtract 125 from both sides
425 - 125 ≥ 125 + 50n - 125
300≥ 50n
Divide both sides by 50
300/50≥50n/50
6 ≥n
Rearrange
n≤6
<em>Hence the maximum number of days for which a car could be rented if the total cost was $425 is 6days</em>
<em></em>
Answer:
165 liters of 15% solution
Step-by-step explanation:
15F + 65S = 60(1650)
F + S = 1650
F = 1650-S
15(1650-S) +65S = 99000
50S = 99000-24750= 74250
S = 74250/50 = 7425/5 = 1485 liters of 65% solution
F = 1650-1485 = 165 liters of 15% solution
65 is much closer to 60 than 15 is, so you know there will be mostly 65% solution with relatively little 15%
Hope this helps, have a nice day/night! :D
Answer:
$0 < p ≤ $25
Step-by-step explanation:
We know that coach Rivas can spend up to $750 on 30 swimsuits.
This means that the maximum cost that the coach can afford to pay is $750, then if the cost for the 30 swimsuits is C, we have the inequality:
C ≤ $750
Now, if each swimsuit costs p, then 30 of them costs 30 times p, then the cost of the swimsuits is:
C = 30*p
Then we have the inequality:
30*p ≤ $750.
To find the possible values of p, we just need to isolate p in one side of the inequality.
So we can divide both sides by 30 to get:
(30*p)/30 ≤ $750/30
p ≤ $25
And we also should add the restriction:
$0 < p ≤ $25
Because a swimsuit can not cost 0 dollars or less than that.
Then the inequality that represents the possible values of p is:
$0 < p ≤ $25
Answer:
we need the other options to find out whats not equivalent to that problem.
