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katrin [286]
2 years ago
11

In a right triangle, one of the legs is 5 cm smaller than the hypotenuse, and the other leg is 10 cm smaller than the hypotenuse

. Find the length of the hypotenuse.
Mathematics
1 answer:
nata0808 [166]2 years ago
3 0

Answer:

25 cm.

Step-by-step explanation:

If the hypotenuse is  x cm long the 2 legs are  x-5 and x-10 cm long.

So by the Pythagoras theorem:

x^2 = (x - 5)^2 + (x - 10)^2

x^2 = x^2 - 10x + 25 + x^2 - 20x + 100

x^2 - 30x + 125 = 0

(x - 5)(x - 25) = 0

x = 5, 25

We can discard x = 5 because that would make the lengths of the legs negative so the hypotenuse = 25 cm long.

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Step-by-step explanation:

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A jumbo crayon is composed of a cylinder with a conical tip. The cylinder is 12 cm tall with a radius of 1.5 cm, and the cone ha
s2008m [1.1K]

Answer:

Part 1) The  lateral area of the cone is LA=2\pi\ cm^{2}

Part 2) The lateral surface area of the cylinder is LA=36\pi\ cm^{2}

Part 3) The surface area of the crayon is SA=41.50\pi\ cm^{2}

Step-by-step explanation:

Part 1) Find the  lateral area of the cone  

The lateral area of the cone is equal to

LA=\pi rl

we have

r=1\ cm

l=2\ cm

substitute

LA=\pi (1)(2)

LA=2\pi\ cm^{2}

Part 2) Find the lateral surface area of the cylinder

The lateral area of the cylinder is equal to

LA=2\pi rh

we have

r=1.5\ cm

h=12\ cm

substitute

LA=2\pi (1.5)(12)

LA=36\pi\ cm^{2}

Part 3) Find the surface area of the crayon

The surface area of the crayon is equal to the lateral area of the cone, plus the lateral area of the cylinder, plus the top area of the cylinder plus the bottom base of the crayon

<em>Find the area of the bottom base of the crayon</em>

A=\pi[r2^{2}-r1^{2}]

where

r2 is the radius of the cylinder

r1 is the radius of the cone

substitute

A=\pi[1.5^{2}-1^{2}]

A=1.25\pi\ cm^{2}

<em>Find the area of the top base of the cylinder</em>

A=\pi(1.5)^{2}=2.25\pi\ cm^{2}

<em>Find the surface area</em>

SA=2\pi+36\pi+2.25\pi+1.25\pi=41.50\pi\ cm^{2}

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Answer:

x = 4 and -10

Step-by-step explanation:

Given the equation

x²+6x-40= 0

The common factors to use for the factorisation are +10 and -4

x²+(10x-4x)-40=0

(x²+10x)-(4x-40) = 0

x(x+10)-4(x+10) = 0

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The angles in a triangle are in the ratio 1:2:3 a) Show that the triangle is a right -angled triangle b) The hypotenuse of the t
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Answer:

8.5 cm

Step-by-step explanation:

Angles of the triangle:

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