All categories

3 years ago

Factor 3x^2-19x+20

Mathematics

1 answer:

dusya [7]3 years ago

4 0

Answer:

(3x-4)(x-5)

Step-by-step explanation:

This is in the form

ax²+bx+c.

To factor this, we find factors of a·c that sum to b; this means factors of 3(20) = 60 that sum to -19:

60 = 1(60) or -1(-60); 2(30) or -2(-30); 3(20) or -3(-20); 4(15) or -4(-15); 5(12) or -5(-12); 6(10) or -6(-10). The only of these that sum to -19 are -4 and -15. This means we will split up -19x into -4x and -15x:

3x²-4x-15x+20

Next we group the first two terms and the last two terms:

(3x²-4x)+(-15x+20)

Factor out the GCF of each group. For the first group, this is x:

x(3x-4)

For the second group, this is -5:

-5(3x-4)

The common factor for these two groups is (3x-4):

(3x-4)(x-5)

You might be interested in

Nick is a great baby sitter.He makes $9 an hour.Julia is an even better babysitter She makes $12 an hour.Julia works 6 hours eac

serg [7]

Answer:

Nick has to work 8 hours

Step-by-step explanation:

Nick makes 9 works x

Julia makes 12 works 6

first find out how much Julia makes you can do that by multiplying 12 by 6 witch = 72

and we know we are trying to find how many hours Nick needs to work to equal Julia so we knew they are equal

so we have 9X=72

we just have to solve...

divide 72 by 9

leaving use with X=8

4 0

3 years ago

Please help me

Whitepunk [10]

First solve your inequality step by step.

y+15<3

= y<-12

Answer is A. y<-12

Answer will help you.

Brainliest answer and Verified answers.

4 0

3 years ago

The following statement is either true (in all cases) or false (for at least one example). If false, construct a specific e

matrenka [14]

Answer:

False, counterexample below

Step-by-step explanation:

Denote the unit vectors of R^3 by $e_1=(1,0,0), e_2=(0,1,0), e_3=(0,0,1)$ . Now consider $v_1=e_1, v_2=2e_1$ and $v_3=e_3$ . We have that $v_1, v_2,v_3 \in \mathbb{R}^3$ . Also, the vector $v_3$ is not a linear combination of $v_1, v_2$ because any linear combination of these two vectors will have third coordinate zero, but v_3 has third coordinate 1 so they can't be equal.

However, the set $\{v_1, v_2,v_3\}$ is not linearly independent, because $2v_1-v_2+0v_3=0$ is a non-trivial linear combination of these vectors that equals zero.

4 0

3 years ago

a swimming pool charges £3.60 for entry. you can save 1/3 of entry fee with a membership card. on his first visit, ken spends £5

nikitadnepr [17]

Answer:

Step-by-step explanation:

You save ⅓ of entry fee, so you save 1.20 and you pay 2.40. We only really care about the 1.20 reduction. 5 / 1.2 = 4.16 so he must go 5 times to get the 5 back

8 0

1 year ago

0.4 times 0.59<br> sgaehags

ra1l [238]

Answer:

0.236

Step-by-step explanation:

Multiply 0.4 by 0.59

hopes this helps have a good day :) <3

brainlest???

5 0

2 years ago

Factor 3x^2-19x+20 ​

Factor 3x^2-19x+20