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OLga [1]
3 years ago
6

Find the total amount owed, to the nearest cent, for the following simple interest loans. (3 points each)

Mathematics
2 answers:
LUCKY_DIMON [66]3 years ago
5 0

Answer:

a. 90.04

b. 446.05

PIT_PIT [208]3 years ago
4 0
Since the question is partial, i will assume 2 scenarios:
They need to raise 1000 income
They need to make 1000 as profit
If $1000 as income:
Each ticket costs $15, so tickets would bring them $1000 income. Fractional ticket is not possible, so rounding gives us 67 tickets as the answer.

If $1000 as profit:
Their cost of renting is $700. We know that .
So, . So, to raise $1700, we need tickets. Fractional ticket is not possible, so rounding gives us 114 tickets as the answer.

ANSWER:
If need to raise atleast $1000 as income, they need to sell 67 tickets.
If need to raise atleast $1000 as profit, they need to sell 114 tickets.
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Which shows a correct way to determine the volume of the right rectangular prism?
ioda

Answer:

Number 4

Step-by-step explanation:

The formula for a right rectangular prism is width*height*length

4 0
4 years ago
Can someone please help?
Firlakuza [10]

Answer:

1. x+4x

2. 5x

3. 6\frac{7}{x}

4. 4x-2x+15

5. (6+x)^2

Step-by-step explanation:

To write expressions remember these key words:

  • a number is a variable like x
  • sum is +
  • difference and subtracted is -
  • quotient is ÷
  • product is ×
  • reciprocal means flip like \frac{1}{9}---> \frac{9}{1}
  • square is an exponent of 2 like x^2

1. x+4x

2. 5x

3. 6\frac{7}{x}

Remember a quotient would be \frac{x}{7}but the reciprocal is \frac{7}{x}.

4. 4x-2x+15

5. (6+x)^2

6 0
3 years ago
Mikes favorite peaches are $2.50 per pound at the local farmers market. She bought 13.5 pounds. how much did she spend?
True [87]
2.50*13.5=33.75. She spent $33.75.
8 0
3 years ago
the marks in an examination for a Physics paper have normal distribution with mean μ and variance σ2 . 10% of the students obtai
Blababa [14]

Let X be the random variable for the number of marks a given student receives on the exam.

10% of students obtain more than 75 marks, so

P(X>75)=P\left(\dfrac{X-\mu}\sigma>\dfrac{75-\mu}\sigma\right)=P(Z>z_1)=0.10

where Z follows a standard normal distribution. The critical value for an upper-tail probability of 10% is

P(Z>z_1)=1-F_Z(z_1)=0.10\implies z_1=F_Z^{-1}(0.90)

where F_Z(z)=P(Z\le z) denotes the CDF of Z, and F_Z^{-1} denotes the inverse CDF. We have

z_1=F_Z^{-1}(0.90)\approx1.2816

Similarly, because 20% of students obtain less than 40 marks, we have

P(X

so that

P(Z

Then \mu,\sigma are such that

\dfrac{75-\mu}\sigma\approx1.2816\implies75\approx\mu+1.2816\sigma

\dfrac{40-\mu}\sigma\approx-0.8416\implies40\approx\mu-0.8416\sigma

and we find

\mu\approx53.8739,\sigma\approx16.4848

3 0
4 years ago
Solve for Unknown: x/10=43/46.
sergey [27]

Answer:

9

Step-by-step explanation:

x= 430/46

x=9.35 approximately 9( nearest whole number)

4 0
2 years ago
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