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3 years ago

12

I need the answers for this question.

1 answer:

nadya68 [22]3 years ago

7 0

Answer:

7

Step-by-step explanation:

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Type the correct answer in each box. Use numerals instead of words.

emmainna [20.7K]

Answer:

(x +5)^2 = -2

Step-by-step explanation:

We can subtract the constant to get ...

x^2 +10x = -27

Then add the square of half the x-coefficient:

x^2 +10x +5^2 = -27 +5^2

(x +5)^2 = -2 . . . . . . write as a square

5 0

3 years ago

Read 2 more answers

Find the extreme values of the function f(x, y) = 4x2 + 6y2 on the circle x2 + y2 = 1.

julia-pushkina [17]

Answer with Step-by-step explanation:

We are given that

$f(x,y)=4x^2+6y^2$

Let g(x,y)= $x^2+y^2=1$

We have to find the extreme values of the given function

$\nabla f(x,y)$

$\nabla g(x,y)=$

Using Lagrange multipliers

$\nabla f(x,y)=\lambda \nabla g(x,y)$

$f_x=\lambda g_x$

$8x=\lambda 2x$

Possible value x=0 or $\lambda=4$

If x=0 then substitute the value in g(x,y)

Then, we get $y=\pm 1$

$f_y=\lambda g_y$

$12y=\lambda 2y$

If $\lambda=4$ and substitute in the equation

Then , we get possible value of y=0

When y=0 substitute in g(x,y) then we get

$x=\pm 1$

Hence, function has possible extreme values at points (0,1),(0,-1), (1,0) and (-1,0).

$f(0,1)=6$

$f(0,-1)=6$

$f(1,0)=4$

$f(-1,0)=4$

Therefore, the maximum value of f on the circle $x^2+y^2=1$ is $f(0,\pm1)=6$ and minimum value of $f(\pm1,0)=4$

7 0

3 years ago

Larry made 3 batches of punch. Each batch uses 24 fluid ounces of lemon juice and 3 pints of orange juice. If each serving is 1

Helga [31]

24*3=72

72*3=216

3*2=6

216+6=222

the answer is 222

6 0

3 years ago

The hypotenuse of a right triangle is 13cm long. the longer leg is 7 cm longer than the shorter leg. find the side lengths of th

Ad libitum [116K]

$5^2 + 12^2 = 13^2$

is the second or third Pythagorean triple on the list, which gives us the answer directly.

But if we didn't know that, let x be the short leg:

$x^2 + (x+7)^2 = 13^2$

$2x^2 + 14 x + 49 - 169 = 0$

$x^2 + 7x - 60 = 0$

$(x+12)(x-5)=0$

Rejecting the negative root, x=5, other side 12, the Pythagorean triple we found.

8 0

3 years ago

P= x/3 and x = 1/2 y. Write p in terms of y

Finger [1]

Answer:

p = 1/2y - 3

Step-by-step explanation:

p=x/3 and x=1/2y [replace the "x" to solve]

p = (1/2y)/3

8 0

3 years ago