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mr_godi [17]
3 years ago
9

Please simplify the following expression: -5-3x-x-(-16)

Mathematics
1 answer:
IrinaVladis [17]3 years ago
8 0


So, this will become:

-4x + 11

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Find the value of f(-1) for the function below
mrs_skeptik [129]

Put the value of x = -1 to the equation of a function f(x):

f(x)=\dfrac{2}{3}\times3^{3x+12}\\\\f(-1)=\dfrac{2}{3}\times3^{3(-1)+12}=\dfrac{2}{3}\times3^{-3+12}=\dfrac{2}{3}\times3^9=\dfrac{2}{1}\times3^8=13,122\to\boxed{B.}

8 0
4 years ago
an inverted conical water tank with a height of 20 ft and a radius of 8 ft is drained through a hole in the vertex (bottom) at a
viktelen [127]

Answer:

the rate of change of the water depth when the water depth is 10 ft is;  \mathbf{\dfrac{dh}{dt}  = \dfrac{-25}{100  \pi} \  \ ft/s}

Step-by-step explanation:

Given that:

the inverted conical water tank with a height of 20 ft and a radius of 8 ft  is drained through a hole in the vertex (bottom) at a rate of 4 ft^3/sec.

We are meant to find the  rate of change of the water depth when the water depth is 10 ft.

The diagrammatic expression below clearly interprets the question.

From the image below, assuming h = the depth of the tank at  a time t and r = radius of the cone shaped at a time t

Then the similar triangles  ΔOCD and ΔOAB is as follows:

\dfrac{h}{r}= \dfrac{20}{8}    ( similar triangle property)

\dfrac{h}{r}= \dfrac{5}{2}

\dfrac{h}{r}= 2.5

h = 2.5r

r = \dfrac{h}{2.5}

The volume of the water in the tank is represented by the equation:

V = \dfrac{1}{3} \pi r^2 h

V = \dfrac{1}{3} \pi (\dfrac{h^2}{6.25}) h

V = \dfrac{1}{18.75} \pi \ h^3

The rate of change of the water depth  is :

\dfrac{dv}{dt}= \dfrac{\pi r^2}{6.25}\  \dfrac{dh}{dt}

Since the water is drained  through a hole in the vertex (bottom) at a rate of 4 ft^3/sec

Then,

\dfrac{dv}{dt}= - 4  \ ft^3/sec

Therefore,

-4 = \dfrac{\pi r^2}{6.25}\  \dfrac{dh}{dt}

the rate of change of the water at depth h = 10 ft is:

-4 = \dfrac{ 100 \ \pi }{6.25}\  \dfrac{dh}{dt}

100 \pi \dfrac{dh}{dt}  = -4 \times 6.25

100  \pi \dfrac{dh}{dt}  = -25

\dfrac{dh}{dt}  = \dfrac{-25}{100  \pi}

Thus, the rate of change of the water depth when the water depth is 10 ft is;  \mathtt{\dfrac{dh}{dt}  = \dfrac{-25}{100  \pi} \  \ ft/s}

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4 years ago
The members of a class voted to visit the zoo, museum, or science center on their next field trip. If the zoo got 33% of the vot
Alenkasestr [34]

Answer:

D

Step-by-step explanation:

100-33=67

67-29=38

38%

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3 years ago
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Answer:x

Step-by-step explanation:

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Y=tan(x-30) period and amplitude ​
mina [271]

Answer:

No amplitude

Period is pi

Step-by-step explanation:

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