Answer: Average rates of change for Bird A is 0.045 and for Bird B is 3.816.
Step-by-step explanation: Through its graph, a function can be analyzed and be identified its attributes. Average Rate of Change is the ratio of change in the function values to the change of x-value, i.e., it is the slope of the function in a specific interval of x. With the Average it is possible to compare two function.
<u>Average Rate of Change</u>
<em><u>Bird A</u></em>:
For the interval [0,18]:
x₁ = 0 f(0) = 8.3
x₂ = 18 f(18) = 9.1
Average = 
Average = 
Average = 0.045
<em><u>Bird B</u></em>: y = 3.6(1.06)x
For the interval [0,18]:
x₁ = 0 y = 3.6(1.06)0 = 0
x₂ = 18 y = 3.6(1.06)18 = 68.7
Average =
Average = 
Average = 3.816
The Average Rate for Change for Bird A is 0.045 and for Bird B is 3.816. This means that the population of Bird B increase in rate faster than the population of Bird A.
15+5•y/2
15+5•4 / 2
15+20 / 2
15+10
=25
The volume of cone B will be 6 cubic units.
<h3>What is the volume of the cone?</h3>
Let h be the height of the cone and A be the base area of the cone.
Then the volume of the cone will be
Volume = (1/3) × A × h
Consider cone A and cone B.
The bases of the cones are congruent.
The height of cone A is 4 times larger than the height of cone B.
The volume of cone A is 24.
24 = (1/3) Ahₐ
Then the volume of the cone B will be
Simplify the expression, then the volume will be
V = 1/4 x (1/3)Ahₐ
V = 1/4 x 24
V = 6 cubic units
The volume of cone B will be 6 cubic units.
More about the volume of the cone link is given below.
brainly.com/question/1984638
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Answer:
dependent events since P(A and B) is not equal to P(A) * P(B)
Step-by-step explanation:
According to the Question,
- Given, The probability that Jane will go to a ballgame (event A) on a Monday is 0.73, and the probability that Kate will go to a ballgame (event B) the same day is 0.61. The probability that Kate and Jane both go to the ballgame on Monday is 0.52.
Thus, The events A, B and A∩B are:
A - Jane will go to a ballgame on Monday;
B - Kate will go to a ballgame on Monday;
A∩B - Kate and Jane both go to the ballgame on Monday.
- P(A)=0.73, P(B)=0.61, P(A∩B)=0.52.
- Pr(A)⋅Pr(B) = 0.73⋅0.61 = 0.4453 ≠ 0.52
So, events A and B are dependent events since P(A and B) is not equal to P(A) * P(B)
Answer:
p(t) = 100%·2^(-t/1.32)
Step-by-step explanation:
The equation for exponential decay is ...
(remaining amount) = (initial amount)·2^(-t/(half-life))
Here, we can represent the percentage remaining by p(t) and the initial amount by 100%. Then, for a half-life of 1.32 minutes, the amount remaining is ...
p(t) = 100%·2^(-t/1.32) . . . . . where t is in minutes
_____
Alternate functional forms are possible, such as ...
p(t) = 100%·e^(-0.525112t)
p(t) = 100%·0.591489^t
