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Svetach [21]
3 years ago
14

Given f(x)=5x^2+3 and g(x)=7x-5. Find (f-g)(x) and its domain.

Mathematics
1 answer:
Alekssandra [29.7K]3 years ago
4 0

Answer:7

Step-by-step explanation:

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In the data set below, what is the mean absolute deviation?
lbvjy [14]

Add the numbers and divide by 5 to get a mean of 6.4

8 - 6.4 = 1.6

4 - 6.4 = -2.4

7 - 6.4 = 0.6

8 - 6.4 = 1.6

5 - 6.4 = -1.4

Add the absolute value of each: 1.6 + 2.4 + 0.6 + 1.6 + 1.4 = 7.6

Divide by 5 = 1.52

1.5

3 0
2 years ago
Drag and drop question I need help on ASAP
klasskru [66]

[] Similar

-> The triangles are similar because they were "mirrored" by the...

[] SSS

-> ... by the SSS similarity theorem, the sides are...

[] Proportional

-> ... the sides are proportional.

[] AB/AC

-> Since the sides are proportional, dividing corresponding sides will leave us with the same number

[] For the last two I think I am missing some information as I do not have any numbers and know where they got 85 from.

Have a nice day!

     I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

- Heather

3 0
3 years ago
What is two over twelve + four over nine
noname [10]

Answer:

2/3

Step-by-step explanation:

2/12+4/9

Find a common denominator

16/72+ 32/72

48/72

Simplify

=2/3

Hope this helps

3 0
3 years ago
I really really really really really really really really need help
Effectus [21]

The answer would be 3.8.

So, to get 3 to 4, you would have to multiply 3 by something to get to 4. So you would divide 4 by 3 and get 1.3. So then you would divide 5 by 1.3 to solve for k, since k times 1.3 equals 5.

5 ÷ 1.3 = 3.8.

4 0
3 years ago
The mean amount purchased by a typical customer at Churchill’s Grocery Store is $23.50, with a standard deviation of $5.00. Assu
m_a_m_a [10]

Answer: 0.0170

Step-by-step explanation:

Given : The mean amount purchased by a typical customer at Churchill’s Grocery Store is $23.50, with a standard deviation of $5.00.

i.e. \mu=23.50

\sigma=5

We assume the distribution of amounts purchased follows the normal distribution.

Sample size : n=50

Let \overline{x} be the sample mean.

Formula : z=\dfrac{\overline{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}

Then, the probability that the sample mean is at least $25.00 will be :-

P(\overline{x}\geq\25.00)=P(\dfrac{\overline{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}\geq\dfrac{25-23.50}{\dfrac{5}{\sqrt{50}}})\\\\=P(z\geq2.12)\\\\=1-P(z

Hence, the likelihood the sample mean is at least $25.00= 0.0170

5 0
3 years ago
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