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marta [7]
3 years ago
14

Write the difference 40 – (–51) as a sum. Then simplify.

Mathematics
1 answer:
san4es73 [151]3 years ago
3 0

the answer is 91. because 40 - (- 51)    the negative would be multiply by -51 making negative -51 a positive

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Natali [406]

Answer:

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7 0
2 years ago
FInd an equation of the line that passes through the point (3,-5) and is parallel to 4x=1+2y
kow [346]

Answer:

y=2x-11

Step-by-step explanation:

Put it in the form y=mx+b=>y=2x-1/2. Instead of -1/2, put it as b, since you want it to go through 3,-5. y=2m+b when it goes through (3,-5) happens when -5=3*2-b. Do algebra, and get b as 11. That means the equation is y=2x-11.

8 0
3 years ago
At a fair, each person can spin two wheels of chance. The first wheel has the letters F, A, I, and R. The second wheel has the n
pickupchik [31]

Answer:

12 possible outcomes.

Sample space:

\begin{array}{cccc}(F,1)&(A,1)&(I,1)&(R,1)\\(F,2)&(A,2)&(I,2)&(R,2)\\(F,3&(A,3)&(I,3)&(R,13)\end{array}

Step-by-step explanation:

The collection of all possible outcomes of a probability experiment forms a set that is known as the sample space.

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2. There are three possible outcomes for the second wheel: 1, 2 and 3

So, the sample space is

\begin{array}{cccc}(F,1)&(A,1)&(I,1)&(R,1)\\(F,2)&(A,2)&(I,2)&(R,2)\\(F,3&(A,3)&(I,3)&(R,13)\end{array}

4 0
3 years ago
During a science experiment, the temperature of the solution in beaker one was 5° below zero. The temperature of a solution in b
Lana71 [14]
<span>5° below zero is -5 degrees
</span><span>The temperature of a solution in beaker two what is the opposite of the temperature in beaker one so it's 5 degrees above zero
</span>
answer
<span>5° above zero</span>
4 0
3 years ago
The graph below shows two polynomial functions, f(x) and g(x): Graph of f of x equals x squared minus 2 x plus 1. Graph of g of
IceJOKER [234]

9514 1404 393

Answer:

  (c)  f(x) is an even degree polynomial with a positive leading coefficient.

Step-by-step explanation:

The leading terms of the two functions are ...

  f(x): x² (even degree, positive coefficient: 1)

  g(x): x³ (odd degree, positive coefficient: 1)

Then it is true that ...

  f(x) is an even degree polynomial with a positive leading coefficient

8 0
3 years ago
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