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horrorfan [7]
3 years ago
5

Starting from the base of the hill, Kit climbed up the hill 87 ft. After taking in the view, she then climbed down the hill 39 f

t and then back up the hill 7 ft to a stream where she rested. How high up the hill did Kit stop to rest?
Mathematics
2 answers:
timofeeve [1]3 years ago
8 0
The awnser is 55 ft i believe
Lelechka [254]3 years ago
4 0
Well, she climbed 87ft up, subtract 39ft from that, and you will get 48ftt, then add the 7ft that she climbed to get to the stream and you will get your answer. does that make sense? 
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Answer:

36 in³

Step-by-step explanation:

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For same r and h,

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Find the coordinates of the points of intersection of the graph of y=13−x with the axes and compute the area of the right triang
Ymorist [56]

the coordinates of the points of intersection of the graph of y=13−x with the axes

Given equation is y=13-x

x axis is x=0

y axis is y=0

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y = 13 - x

y = 13 - 0 = 13

Plug in the value of y=0 and find out x

0 = 13 - x

x= 13

So coordinate axis

x= (13,0)

y= (0,13)

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6 0
3 years ago
HELP<br> Find the measure of angle z in the following figure,
Tema [17]

Answer:

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Step-by-step explanation:

<u>All three angles of a triangle add up to 180°</u>. In this image, you can see that the angle ∠ACD is 130°. Because ∠ACB and ∠ACD are supplementary angles it means that their angles equal 180° when added together.

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180° - 130° = 50°

Since we now know that ∠ACB is 50°, we can subtract our two angles from 180° to get the measurement for angle z.

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maxonik [38]

Given:

The red figure dilated with a scale factor of s=\dfrac{1}{3} and the center of dilation is at the point (4,2) to get the green figure.

To find:

The coordinates of C' and A.

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(x,y)\to (k(x-a)+a,k(y-b)+b)

In given problem, the scale factor is \dfrac{1}{3} and the center of dilation is at (4,2).

(x,y)\to (\dfrac{1}{3}(x-4)+4,\dfrac{1}{3}(y-2)+2)            ...(i)

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Using (i), we get

C(-2,11)\to C'(\dfrac{1}{3}(-2-4)+4,\dfrac{1}{3}(11-2)+2)

C(-2,11)\to C'(\dfrac{1}{3}(-6)+4,\dfrac{1}{3}(9)+2)

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A'(\dfrac{1}{3}(m-4)+4,\dfrac{1}{3}(n-2)+2)=A'(8,4)

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n=8

Therefore, the coordinates of point A are (16,8).

4 0
3 years ago
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