Answer:
.
Step-by-step explanation:
Start by finding the slope of the line perpendicular to 
.
The slope of is 
.
In a plane, if two lines are perpendicular to one another, the product of their slopes would be 
.
Let 
denote the slope of the line perpendicular to . The expression 
would denote the product of the slopes of these two lines.
Since these two lines are perpendicular to one another, 
. Solve for : 
.
The 
is a point on the requested line. (That is, 
and 
.) The slope of that line is found to be . The equation of that line in the point-slope form would be:
.
Rewrite this point-slope form equation into the slope-intercept form:
.
2(3)=6. A=3 you substitute the 3 for A to get 6 because 2 times 3 is 6
None, Karen doesn't read.
P(heads, and even and blue) = 1/2 *3/6 *1/4=1/2*1/2*1/4=1/16
P(heads, and 5, and green) = 1/2*1/6*1/4=1/48
P((heads or tail), and odd, and red)= (1/2+1/2)*3/6*1/4=1*1/2*1/4 = 1/8
P((heads or tail), and 3, and yellow)= (1/2+1/2)*1/6*1/4=1*1/6*1/4=1/24
P(tails, and prime, and not green) = 1/2 *3/6*3/4= 1/2*1/2*3/4=3/16
(Prime numbers here are 2,3 and 5)
Answer: B ,I just completed the assignment
