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bonufazy [111]
2 years ago
6

16.

Mathematics
2 answers:
LekaFEV [45]2 years ago
7 0

Answer:

B. 0,3

Step-by-step explanation:

I took the test and checked the answer, 0,3 is correct.

KatRina [158]2 years ago
3 0

Answer:

D

Step-by-step explanation:

is the correct answer i believe.

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Please help Which of the following inequalities is graphed on the coordinate plane?
Gekata [30.6K]

Answer:

The inequality which represents the graph is y ≤ -2x + 1 ⇒ A

Step-by-step explanation:

To solve the question you must know some facts about inequalities

  • If the sign of inequality is ≥ or ≤, then it represents graphically by a solid line
  • If the sign of inequality is > or <, then it represents graphically by a dashed line
  • If the sign of inequality is > or ≥, then the area of the solutions should be over the line
  • If the sign of inequality is < or ≤, then the area of the solutions should be below the line

Let us study the graph and find the correct answer

∵ The line represented the inequality is solid

∴ The sign of inequality is ≥ or ≤

→ That means the answer is A or B

∵ The shaded area is the area of the solutions of the inequality

∵ The shaded area is below the line

∴ The sign of inequality must be ≤

→ That means the correct answer is A

∴ The inequality which represents the graph is y ≤ -2x + 1

3 0
2 years ago
Deep mixing is a ground improvement method developed for soft soils like​ clay, silt, and peat. Civil engineers investigated the
Kitty [74]

Answer:

a)  0.9078

b) 0.9832

c) T = 2.9867

Step-by-step explanation:

Given:-

T  ~ N (2.7 , 0.8 )

Find:

Find the probability that the tip resistance will fall between 1.3 and 4.0 MPa.

Find the probability that the tip resistance will exceed 1.0 MPa.

Find a value of tip​ resistance, T, such that 36​% of all soil samples have tip resistance values that exceed T

Solution:

a) To find the P ( 1.3 < x < 4.0 ) we will first compute the z-score values:

        P (1.3 < x < 4.0 ) = P ( (1.3 - 2.7)/0.8 < Z < (4.0 - 2.7)/0.8)

        P (1.3 < x < 4.0 ) = P ( -1.75 < Z < 1.625)

- Using the Z-table values we can evaluate the probability:

       P (1.3 < x < 4.0 ) = P ( -1.75 < Z < 1.625) = 0.9078

b) To find the P ( x > 1 ) we will first compute the z-score values:

        P ( x > 1.0 ) = P ( Z > (1.0 - 2.7)/0.8)

        P ( x > 1.0 ) = P ( Z > -2.125)

- Using the Z-table values we can evaluate the probability:

       P ( x > 1.0 ) = P ( Z > -2.125) = 0.9832

c) To find the P ( x > T ) we will first compute the z-score values:

       P ( x > T ) = P ( Z > (T - 2.7)/0.8) = 0.36

  - We will search for the z value with the condition above from Z-table.

       P ( Z > (T - 2.7)/0.8) = 0.36,  Z = 0.358375

  - Hence, we calculate for T:

        T = 0.358375*0.8 + 2.7

        T = 2.9867

5 0
2 years ago
Identify the number types that describe a bar over 7
Morgarella [4.7K]

Answer:Type of Number Example

Prime Number P=2,3,5,7,11,13,17,…

Composite Number 4,6,8,9,10,12,...

Whole Numbers W=0,1,2,3,4,…

Integers Z=…,−3,−2,−1,0,1,2,3,…

Step-by-step explanation:

8 0
1 year ago
32 athletes are going camping for the weekend. Three athletes can sleep in one tent. What is the minimum number of tents that wi
Yuliya22 [10]

Answer:

11

Step-by-step explanation:

6 0
2 years ago
Give a 98% confidence interval for one population mean, given asample of 28 data points with sample mean 30.0 and sample standar
klio [65]

We have a sample of 28 data points. The sample mean is 30.0 and the sample standard deviation is 2.40. The confidence level required is 98%. Then, we calculate α by:

\begin{gathered} 1-\alpha=0.98 \\ \alpha=0.02 \end{gathered}

The confidence interval for the population mean, given the sample mean μ and the sample standard deviation σ, can be calculated as:

CI(\mu)=\lbrack x-Z_{1-\frac{\alpha}{2}}\cdot\frac{\sigma}{\sqrt[]{n}},x+Z_{1-\frac{\alpha}{2}}\cdot\frac{\sigma}{\sqrt[]{n}}\rbrack

Where n is the sample size, and Z is the z-score for 1 - α/2. Using the known values:

CI(\mu)=\lbrack30.0-Z_{0.99}\cdot\frac{2.40}{\sqrt[]{28}},30.0+Z_{0.99}\cdot\frac{2.40}{\sqrt[]{28}}\rbrack

Where (from tables):

Z_{0.99}=2.33

Finally, the interval at 98% confidence level is:

CI(\mu)=\lbrack28.94,31.06\rbrack

4 0
1 year ago
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