Answer:
-3
Step-by-step explanation:
f(x)=-2x+7
f(5)=-2×5+7
=-10+7
=-3
Answer:
Step-by-step explanation:
You have right triangles, so use the Pythagorean Theorem
x = length of diagonal
8² + 10² = x²
164 = x²
x = √164 = 2√41 ≅ 12.8 in
Answer:
V= 105cm^3
Step-by-step explanation:
V=volume
(1/3)V+40=(5/7)V
(5/7)V-(1/3)V=40
(15/21)V-(7/21)V=40
(8/21)V=40
(21/8)(8/21)V=(21/8)(40
V=21*5
V=105 cm3
(1/3)(105)=35, 35+40=75, 75/105=15/21=5/7
Answer:
Therefore the required polynomial is
M(x)=0.83(x³+4x²+16x+64)
Step-by-step explanation:
Given that M is a polynomial of degree 3.
So, it has three zeros.
Let the polynomial be
M(x) =a(x-p)(x-q)(x-r)
The two zeros of the polynomial are -4 and 4i.
Since 4i is a complex number. Then the conjugate of 4i is also a zero of the polynomial i.e -4i.
Then,
M(x)= a{x-(-4)}(x-4i){x-(-4i)}
=a(x+4)(x-4i)(x+4i)
=a(x+4){x²-(4i)²} [ applying the formula (a+b)(a-b)=a²-b²]
=a(x+4)(x²-16i²)
=a(x+4)(x²+16) [∵i² = -1]
=a(x³+4x²+16x+64)
Again given that M(0)= 53.12 . Putting x=0 in the polynomial
53.12 =a(0+4.0+16.0+64)

=0.83
Therefore the required polynomial is
M(x)=0.83(x³+4x²+16x+64)