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Dovator [93]
3 years ago
8

Find the angle, in degrees between 0 and 360∘, which intersects the unit circle at the point (−1/2,3/√2).

Mathematics
1 answer:
Vlada [557]3 years ago
6 0

Answer:

it approx 103.2 degree

Step-by-step explanation:

s=90+tan^-1(1÷3√2)

I add 90 base on the coordinate , taking the centre of the circle place at origin

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Can someone show me how to work out this example?<br><br><br> (5+44+182−20−10)÷(2+5)
lora16 [44]

Answer:

approximately 35.9

Step-by-step explanation:

(5+44+182-20-10)÷(2+5)

(99+182-20-10)÷(7)

(281-20-10)÷(7)

(261-10)÷÷(7)

(251)÷(7)

approximately 35.9

6 0
3 years ago
If QS bisects PQT, SQT=(8x- 25),PQT=(9x+34), and SQR=112, find each measure.
Goryan [66]

The values of the angles are; x = 12°, m∠PQS = 71°, m∠PQT = 142° and m∠TQR = 41°

<h3>What are the measure of the each angle?</h3>

The required angles; x, m∠PQS, m∠PQT, and m∠TQR

The given parameters are bisects ∠PQT

m∠SQT = (8·x - 25)°

m∠PQT = (9·x + 34)°

m∠SQR = 112°

We have;

m∠PQT = m∠SQT + m∠PQS (Angle addition postulate)

m∠SQT ≅ m∠PQS (Angles formed by angle bisector are congruent)

m∠SQT = m∠PQS  by Definition of congruency

m∠PQT = 2 × m∠SQT

Therefore;

(9·x + 34)° = 2 × (8·x - 25)° = (16·x - 50)°

Collecting like terms gives:

(34 + 50)° = 16·x - 9·x = 7·x

7·x = 84°

x = 84°/7 = 12°

x = 12°

m∠SQT = (8·x - 25)°

Therefore;

m∠SQT = (8 × 12 - 25)° = 71°

m∠SQT = 71°

m∠PQT = 2 × m∠SQT

∴ m∠PQT = 2 × 71° = 142°

m∠PQT = 142°

m∠PQS = m∠SQT (Angles formed by the same bisector )

∴ m∠PQS = m∠SQT = 71°

m∠PQS = 71°

m∠SQR = m∠SQT + m∠TQR (Angle addition postulate)

m∠SQT = 71°

∴  m∠SQR = 112° = 71° + m∠TQR

m∠TQR = 112° - 71° = 41°

m∠TQR = 41°

Learn more about angles here:

brainly.com/question/2882938

#SPJ1

4 0
1 year ago
3.452 × 100 =-------------
Lilit [14]

Answer:

345.2

Step-by-step explanation:

1: Move 3.452 to the end of the equation

(3.452 × 100) -> (3.452 × 100 = 3.452)

2: Since 100 has 2 zeros, move the decimal point 2 places to the right.

(3.452 × 100 = 3.452) -> (345.2)

Hope this helps!

7 0
3 years ago
Read 2 more answers
Verify that cos squared A plus Sin squared A is equal to 1 if A is equal to 90 degrees
Scilla [17]

Answer:

see explanation

Step-by-step explanation:

To verify cos²A + sin²A = 1 with A = 90° , then

cos²90° + sin²90°

= (0)² + (1)²

= 0 + 1

= 1

3 0
3 years ago
4th grade homework question 738÷3
Finger [1]
246. (it says my answer is to short but so i have to type useless stuff anyways the answer is 246 lol have a nice day!)
7 0
3 years ago
Read 2 more answers
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