The correct answer for the question that is being presented above is this one: "x = 2; a = 5; b = 3" A 5 inch tall bamboo shoot doubles in height every 3 days. If the equation y=ab^x, where x is the number of doubling periods, represents the height of the bamboo shoot
Answer:
229.5
Step-by-step explanation:
In order to calculate the area of the arrow we need to calculate the area of the body of the arrow, and then the head of the arrow. The body of the arrow is a rectangle meaning that the area (Ar) can be calculated by multiplying the length by the height like so...
Ar = l * h
Ar = 11cm * 12cm
Ar = 132 
Now we need to find the area of the head of the arrow, which is a triangle and therefore we can use the formula for the area of a triangle (At) which is height times base divided by 2...
At = 
At = 
At = 
At = 97.5
Now we simply add both areas together to calculate the total area of the arrow...
132
+ 97.5
= 229.5
Answer:
12
Step-by-step explanation:
This is a joint variation problem:
z varies directly as x and y
Interpreting this;
z ∝ xy
Therefore;
z = kxy
z = 6, x = 2, y = 6
Now find k,
6 = 2 x 6 x k
6 = 12k
k =
To find the value of z;
x = 3, y = 8
z =
x 3 x 8 = 12
Answer:
Solution : Option C
Step-by-step explanation:
We have the equations r² = x² + y², x = r cos(θ), and y = r sin(θ) that can be used to solve this problem. In this case we only need the second two equations ( x = r cos(θ), and y = r sin(θ) ) as we don't need to apply the concept of circles etc here.
Given : x = - 9,
( Substitute r cos(θ) for x )
r cos(θ) = - 9,
r = - 9 / cos(θ)
( Remember that sec is the reciprocal of cos(θ). Substitute sec for 1 / cos(θ) )
r = - 9 sec(θ)
Therefore the third option is the correct solution.
I think the answer is y=-2(x-2)^2+6