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djyliett [7]
3 years ago
13

Inverse of f(x) = 3 + 2 In x?

Mathematics
1 answer:
JulsSmile [24]3 years ago
4 0
This is the inverse of f(x)= -3 - (-2)
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Find the perimeter and area of the figure​
Ludmilka [50]

Answer:

C.

Step-by-step explanation:

C. is the only answer option with the correct perimeter of 18u

area is correct too

5 0
3 years ago
Read 2 more answers
PLEASE HELP ME ASAP!
AleksandrR [38]

Ok so first we find the equation that equals one variable.


2y = -x + 9

3x - 6y = -15


We solve for y.


2y = -x + 9

y = -x/2 + 9/2


Then we plug in this y value into the other equation to keep only one variable so we can solve for it.


3x - 6y = -15

3(-x + 9/2) - 6y = -15

-3x + 27/2 - 6y = -15

-9y + 27/2 = -15

-9y = 3/2

-y = 3/18

y = -3/18


Then we plug in this numerical y-value into the first equation which we found out by solving an equation for y.


y = -x/2 + 9/2

-3/18 = -x/2 + 9/2

-84/18 = -x/2

-x = 9 1/3

x = -28/3


Your answer would be (-28/3, -3/18)


Hope this helps!

6 0
3 years ago
Read 2 more answers
25 Points ! Write a paragraph proof.<br> Given: ∠T and ∠V are right angles.<br> Prove: ∆TUW ∆VWU
vladimir2022 [97]

Answer:

Δ TUW ≅ ΔVWU ⇒ by AAS case

Step-by-step explanation:

* Lets revise the cases of congruent for triangles

- SSS  ⇒ 3 sides in the 1st Δ ≅ 3 sides in the 2nd Δ

- SAS ⇒ 2 sides and including angle in the 1st Δ ≅ 2 sides and  

 including angle in the 2nd Δ  

- ASA ⇒ 2 angles and the side whose joining them in the 1st Δ  

 ≅ 2 angles and the side whose joining them in the 2nd Δ  

- AAS ⇒ 2 angles and one side in the first triangle ≅ 2 angles

 and one side in the 2ndΔ

- HL ⇒ hypotenuse leg of the first right angle triangle ≅ hypotenuse

 leg of the 2nd right angle Δ

* Lets solve the problem

- There are two triangles TUW and VWU

- ∠T and ∠V are right angles

- LINE TW is parallel to line VU

∵ TW // VU and UW is a transversal

∴ m∠VUW = m∠TWU ⇒ alternate angles (Z shape)

- Now we have in the two triangles two pairs of angle equal each

 other and one common side, so we can use the case AAS

- In Δ TUW and ΔVWU

∵ m∠T = m∠V ⇒ given (right angles)

∵ m∠TWU = m∠VUW ⇒ proved

∵ UW = WU ⇒ (common side in the 2 Δ)

∴ Δ TUW ≅ ΔVWU ⇒ by AAS case

7 0
3 years ago
Read 2 more answers
What is 27/64 in simplest form
Sholpan [36]
The fraction is already in simplest form!:)
4 0
3 years ago
Find the area of the compound shape
andrey2020 [161]
This shape is separated into two trapezoids. The equation for the area of a trapezoid is .5(base1 + base2) multiplied by height. Therefore, each half of the compound shape would be equal to .5(12 + 8) * 6 or 10 * 6 = 60. So the area of the total would be 60+60 or 120.
7 0
3 years ago
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