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natali 33 [55]
3 years ago
15

What is the quotient? Negative StartFraction 3 over 8 EndFraction divided by negative one-fourth

Mathematics
1 answer:
anyanavicka [17]3 years ago
6 0

Answer:

\dfrac{3}{2}

Step-by-step explanation:

We are given 2 fractions.

1st fraction is Negative StartFraction 3 over 8

i.e.

-\dfrac{3}{8}

2nd fraction is negative one-fourth

i.e.

-\dfrac{1}{4}

We have to find the quotient when 1st fraction is divided by 2nd fraction.

<u>Definition</u> of quotient is given as:

Quotient is the result obtained when one number is divided by other number.

-\dfrac{3}{8} \div -\dfrac{1}{4} \text{ is to be calculated.}

\div is converted to \times and the 2nd fraction is reversed i.e.

if the fraction is \frac{p}{q} it becomes \frac{q}{p} and the sign \div is changed to \times.

Solving above:

-\dfrac{3}{8} \times -\dfrac{4}{1}\\ \text {Multiplication/Division of 2 negative number gives a positive number}\\\Rightarrow \dfrac{3}{2}

So, the quotient is \frac{3}{2}.

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Answer:

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Step-by-step explanation:

Let's first get the slope of the curve.

[ slope is the derivative of the equation ]

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introduce dy/dx :

\frac{d}{dx} ( {x}^{2}  - xy +  {y}^{2} ) =  \frac{d}{dx} (7) \\  \\ 2x - (y +  \frac{dy}{dx} ) + 2y \frac{dy}{dx}  = 0

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At point (-1, 2):

\frac{dy}{dx}  =  \frac{2 - 2( - 1)}{2(2) - 1}  \\  \\ slope =  \frac{4}{3}

but a tangent has the same slope as the curve:

y = mx + c

m is the slope

c is the y-intercept

At (-1, 2):

2 = ( - 1 \times  \frac{4}{3} ) + c \\  \\ c = 2 +  \frac{4}{3}  \\  \\ c =  \frac{10}{3}

equation:

y =  \frac{4}{3} x +  \frac{10}{3}  \\  \\ { \boxed{3y = 4x + 10}}

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