You have cards with the letters A, B, C, D, E, F, G, H, I, J, K, L, M, N, O, P. Event U is choosing the cards A, B, C
Thepotemich [5.8K]
Answer:
If you are asking how many events use P: 1 event is using the letter P (event W)
Step-by-step explanation:
Why event U cannot be using P: This event is only using the letters A, B, C, and D.
Why event V cannot be using P: This event is only using vowels (A, E, I, O, U)
Answer:
25.9
Step-by-step explanation:
25.9
pi-pi+pi/pi is 0+(1*25.9) which is 25.9
Hope this helps :D
The probability of getting a Club given that the card is a Ten is 0.25.
According to the statement
we have given that the there is a deck of the 52 cards and we have to find the conditional probability that the card is a club and the given card is a 10 number card.
So, For this purpose we know that the
Conditional probability is a measure of the probability of an event occurring, given that another event has already occurred.
And according to this,
The probability P is
P(Club) = 13/52 = 1/4
P(Ten) = 4/52 = 1/13
P(Club and Ten) = (1/4)(1/13) = 1/52
And we know that the
P(Club|Ten) = P(Club and Ten)/P(Ten)
And then substitute the values and it become
= (1/52)/(1/13) = (1/52)(13/1)
= 13/52 = 1/4
= 0.25
So, The probability of getting a Club given that the card is a Ten is 0.25.
Learn more about probability here
brainly.com/question/24756209
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The ratio would be 4:6 because there are 6 number in total and 4 of them are odd numbers.
