Answer:
def calculate_pay(total_worked_hours, rate_per_hour):
if total_worked_hours > 40:
return (40 * rate_per_hour) + ((total_worked_hours - 40) * 2 * rate_per_hour)
else:
return total_worked_hours * rate_per_hour
Explanation:
- Create the calculate_pay function that takes 2 parameters.
- Inside the function check whether the total_worked_hours is greater than 40 and then return the pay by calculating with the help of formula for work over 40 hours.
- Otherwise return the pay by multiplying the total_worked_hours with rate_per_hour.
Answer:
Probability Distribution={(A, 4/7), (B, 2/7), (C, 1/7)}
H(X)=5.4224 bits per symb
H(X|Y="not C")=0.54902 bits per symb
Explanation:
P(B)=2P(C)
P(A)=2P(B)
But
P(A)+P(B)+P(C)=1
4P(C)+2P(C)+P(C)=1
P(C)=1/7
Then
P(A)=4/7
P(B)=2/7
Probability Distribution={(A, 4/7), (B, 2/7), (C, 1/7)}
iii
If X={A,B,C}
and P(Xi)={4/7,2/7,1/7}
where Id =logarithm to base 2
Entropy, H(X)=-{P(A) Id P(A) +P(B) Id P(B) + P(C) Id P(C)}
=-{(1/7)Id1/7 +(2/7)Id(2/7) +(4/7)Id(4/7)}
=5.4224 bits per symb
if P(C) =0
P(A)=2P(B)
P(B)=1/3
P(A)=2/3
H(X|Y="not C")= -(1/3)Id(I/3) -(2/3)Id(2/3)
=0.54902 bits per symb
To make a horizontal line in mathematics you require some sort of constant function. Where no matter the input x the output y will always equal to a certain number n.
For eg. consider n = 2. Hence the graph of line has an equation of y = n making it always intercept in (x, n). As x increases the y is the same therefore the horizontal infinite line emerges.
So to plot or code this kind of program you need to have the same values of y therefore y is a constant function.
Hope this helps.
r3t40
The question above has multiple choices as below;
<span>a. </span>Wear aggregation.
<span>b.
</span>Wear mitigation.
<span>c. </span>Wear prevention
<span>d.
</span>Wear leveling
The answer is d) Wear leveling.
This technique by some SSD controllers to increase the
memory’s lifetime is called wear leveling. The mechanism for this principle is
simple: distribute the entries for all the blocks evenly so that they will wear
out evenly. Flash controller typically manages wear leveling and uses a wear
leveling algorithm to control which physical block to use.
I am not too familiar with the Python language, but the algorithm would be something like this:
1. create a variable for the sums of the number
2. read in how many numbers the user wants to enter (let's call it N)
and then create a for loop:
for N times
read in the next number
increase the sum variable by that number
Hopefully this helps!
