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GarryVolchara [31]
3 years ago
6

BRAINLIEST BRAINLIEST BRAINLIEST BRAINLIEST BRAINLIEST BRAINLIEST BRAINLIEST BRAINLIEST BRAINLIEST BRAINLIEST BRAINLIEST BRAINLI

EST

Computers and Technology
2 answers:
NeX [460]3 years ago
8 0

Answer:

Network

Explanation:

olganol [36]3 years ago
7 0

Answer:

I think the answer is network

hope this helps

have a good day :)

Explanation:

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Make a program that prints each line of its input that mentions fred. (It shouldn’t do anything for other lines of input.) Does
Vitek1552 [10]

Answer:

See Explaination

Explanation:

This assume that input is a file and is given on command line. Please note this will ot print lines with frederick as thats what I feel question is asking for

#!/usr/bin/perl -w

open(FILE, $ARGV[0]) or die("Could not open the file $ARGV[0]");

while ($line = <FILE>){

if($line=~/\s+fred\s+/)

{

print $line;

}

}

close(FILE);

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Matching parentheses. An math expression may have a number of parentheses like (, ), [, ], { and }. Each openning parenthesis (,
Solnce55 [7]
C++ Code

#include
using namespace std;

bool match(const char exp[],const int s)
{
// declare a character array to perform stack operations
char stack[s];

// declare top and initialize to -1 and flag to 0
int top=-1,i,flag=0;

// visit all characters in the expression string
for(i=0;i {
// if the character is [ or ( or { then push it into stack
if(exp[i]=='[' || exp[i]=='(' || exp[i]=='{')
{
top++;
stack[top]=exp[i];
}
// if the character is ] or ) or } then check conditions
else if(exp[i]==']' || exp[i]==')' || exp[i]=='}')
{
// check stack is empty or not
if(top!=-1)
{
// check all possible failure conditions
if(exp[i]==')' && (stack[top] == '{' || stack[top]=='['))
{
flag = 1;
break;
}
else if(exp[i]==']' && (stack[top] == '{' || stack[top]=='('))
{
flag = 1;
break;
}
else if(exp[i]=='}' && (stack[top] == '(' || stack[top]=='['))
{
flag = 1;
break;
}
top--;
}
else
{
flag=1;
break;
}
}
}
// after visiting all characters of expression string check if stack is not empty and flag is 1. if any one of the condition is true return false. otherwise return true

if(top>=0 || flag==1)
return false;
else
return true;
}

int main()
{

// declare character array to store expression
char exp[10000];
cout<<"Enter an Expression"<
// read expression from user
cin.getline(exp, 10000);
int s=0;

// find the length of the expression string
for(int i=0;exp[i]!='\0';i++)
{
s++;
}

// call the match function
bool status = match(exp,s);

// print the result based on value returned by match() function
if(status == 1)
cout<<"true"< else
cout<<"false"<
}


Sample Input/Output is attached

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Where Can I Get Actual Microsoft AZ-900 Exam Questions?
Pachacha [2.7K]

Answer:

Pls check the site "examtopics"

U fill find ur questions there

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