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3 years ago

PLS HELP I NEED TO GET THIS RIGHT WILL MARL BRAINLIEST

Mathematics

1 answer:

emmasim [6.3K]3 years ago

6 0

Answer:

I would say A) 9

Step-by-step explanation:

hope this helps

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There are mangoes and oranges in a basket in the ratio 7: 11. If the total number of fruits is 720, then how many mangoes are th

lbvjy [14]

Answer:

280 mangoes

Step-by-step explanation:

sum the parts of the ratio, 7 + 11 = 18 parts

Divide the total by 18 to find the value of one part of the ratio.

720 ÷ 18 = 40 ← value of 1 part of the ratio , then

7 × 40 = 280 ← number of mangoes

8 0

2 years ago

Read 2 more answers

find the length of the line segment with end points (7,2) and (-4,2) explain how you arrived at your solution

Inga [223]

Answer:

<h2>11 units</h2>

Step-by-step explanation:

Method 1:

The formula of a distance between two points:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

We have the points (7, 2) and (-4, 2). Substitute:

$d=\sqrt{(2-2)^2+(-4-7)^2}=\sqrt{0^2+(-11)^2}=\sqrt{11^2}=11$

Method 2:

Look at the picture. Mark points in the coordinate system.

Read the length of the segment.

6 0

3 years ago

What is the domain of the graphed function?

frosja888 [35]

Yo sup??

Let the function be

y=f(x)

Domain refers to the permissible values of x

since its given that 1<x<5

therefore domain of the given function is x∈(1,5)

Hope this helps.

3 0

3 years ago

1/4 x 2/5 x 3/6 x 4/7 x 5/8 x 6/9 x 7/n=?

postnew [5]

Answer:

c. $\frac{1}{12n} = {[12n]}^{-1}$

Step-by-step explanation:

$[\frac{1}{4}][\frac{2}{5}][\frac{1}{2}][\frac{4}{7}][\frac{5}{8}][\frac{2}{3}][\frac{7}{n}] = \frac{560}{6720n} = [12n]^{-1} = \frac{1}{12n}$

$\frac{2}{3} = \frac{6}{9}\\ \\ \frac{1}{2} = \frac{3}{6}$

* To make this simpler, reduce these two fractions in lowest terms.

I am joyous to assist you anytime.

8 0

3 years ago

In right-angled ∆ ABC, ∟B=90⁰. ∆ ABC is in the first and second quadrant on the graph paper. The coordinates of the points A and

Musya8 [376]

Answer:

The given coordinates of the points A and C of the right triangle ABC are (2, 5) and (-2, 3) respectively

The possible pairs of the coordinates of the point B are found as follows;

1) Draw a horizontal line from the point C to the right and a vertical line down from the point A to get the point B at (2, 3) which is the point of the perpendicular intersection of the two constructed lines above

2) Draw a vertical line from the point C upwards and a horizontal line to the left from the point A to get the point B at (-2, 5) which is the point of the perpendicular intersection of the two newly constructed lines here

Step-by-step explanation:

3 0

3 years ago