Do you mean north east? If it is something else comment below..
Answer: No, it is not possible
A triangle can only have 1 obtuse interior angle, leaving the exterior angle next to it to be acute. For example, if you have an interior angle of 120 (obtuse) then the adjacent exterior angle is 60 (acute)
The other two interior angles must be acute if you go with 1 obtuse angle, which leaves the corresponding exterior angles to be obtuse. If you wanted the exterior angles to be all acute, then you would need 3 obtuse interior angles, but that is not possible.
Why isn't it possible to have 3 obtuse angles? Consider a triangle with interior angles A, B, C. The three angles must add to 180
A+B+C = 180
If A,B,C were all larger than 90, then
A > 90
B > 90
C > 90
A+B+C > 90+90+90
A+B+C > 270
but that contradicts A+B+C being equal to 180
Step-by-step explanation:
Give the first 8 terms of the sequence. a1= -1, a2=2, a[n]=a[n-2](3-a[n-1])
Given
first term a1 = -2
second term a2 = 2
We are to get the first 8 terms. Given the sequence
a[n]=a[n-2](3-a[n-1])
a[3]=a[3-2](3-a[3-1])
a[3]=a[1](3-a[2])
a[3]=-2(3-2)
a3 = -2
a[n]=a[n-2](3-a[n-1])
a[4]=a[4-2](3-a[4-1])
a[4]=a[2](3-a[3])
a[4]=2(3+2)
a4= 10
a[5]=a[n-2](3-a[n-1])
a[5]=a[5-2](3-a[5-1])
a[5]=a[3](3-a[4])
a[5]=-3(3-10)
a5 = -3(-7)
a5 = 21
a[6]=a[n-2](3-a[n-1])
a[6]=a[6-2](3-a[6-1])
a[6]=a[4](3-a[5])
a[6]= 10(3-21)
a6 = 10(-18)
a6 = -180
a[n]=a[n-2](3-a[n-1])
a[7]=a[7-2](3-a[7-1])
a[7]=a[5](3-a[6])
a[7]= 21(3+180)
a7 = 21(183)
a7 = 3,843
a[8]=a[n-2](3-a[n-1])
a[8]=a[8-2](3-a[8-1])
a[8]=a[6](3-a[7])
a[8]=-180(3-3843)
a8 = -180(-3840)
a8 = 691,200
Answer:
see explanation
Step-by-step explanation:
Given
A = 
h(x + y)
Multiply both sides by 2 to eliminate the fraction
2A = h(x + y) ( divide both sides by h )
= x + y ( subtract x from both sides )
y = - x
