The answer to this question is C
Yes, because it is continuous on [0,2] and differentiable on (0,2), the theorem states that there must exist some value c where a line tangent to c is parallel to the secant line through 0 and 2.
Answer:
The correct answer is option A. 90°
Step-by-step explanation:
<u>Points to remember</u>
Measure of angles on the semicircle is 90°
From the figure we can see a semicircle and a triangle inscribes on it.
<u>To find the measure of <XYZ</u>
Here <XYZ is on the semicircle that is angle XYZ is a right angle.
Therefore m<XYZ = 90°
The correct answer is option A. 90°
You will use a2+b2=c2 (squared).The leg will represent the a2 or either b2 and the hypotenuse will be the c2.After filling in the variables you will then subtract the a2 which is the leg from the c2 which is the hypotenuse.And then you will factor it or square root it.If you square root it and it’s not a feasible answer then use the Christmas tree or birthday cake method to factor the answer and then you’ll have the value of b2 which is the unknown leg.
A. The coordinates of the midpoint of CD in terms of p and q is [(4 + p) / 2 , (5 + q) / 2]
B. The coordinates of D, Given that the midpoint of CD is (7, 1) is (10 , -3)
<h3>A. How to determine the mid point</h3>
- Coordinate of C = (4, 5)
- Coordinate of D = (p, q)
- Mid point =?
Mid point = (X , Y)
X = (x₁ + x₂) / 2
X = (4 + p) / 2
Y = (y₁ + y₂) / 2
Y = (5 + q) / 2
Thus,
Mid point = (X , Y)
Mid point = [(4 + p) / 2 , (5 + q) / 2]
<h3>B. How to determine the coordinates of D</h3>
- Mid point = (7, 1)
- Coordinates of D =?
Mid point = (7, 1) = (X , Y)
X = (4 + p) / 2
7 = (4 + p) / 2
Cross multiply
7 × 2 = 4 + p
14 = 4 + p
Collect like terms
p = 14 - 4
p = 10
Y = (5 + q) / 2
1 = (5 + q) / 2
Cross multiply
1 × 2 = 5 + q
2 = 5 + q
Collect like terms
q = 2 - 5
q = -3
Coordinates of D = (p, q)
Coordinates of D = (10 , -3)
Learn more about coordinate geometry:
brainly.com/question/4976351
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