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ser-zykov [4K]
4 years ago
9

Write and equation in standard form for a line that is (a) parallel (b) perpendicular to the line with an equation of y= 3x - 5

that passes through the point (5,8)

Mathematics
1 answer:
KatRina [158]4 years ago
6 0

Answer:

  (a) 3x -y = 7

  (b) x +3y = 29

Step-by-step explanation:

(a) The standard form of the given line is ...

  3x -y = 5

The parallel line will have a constant on the right that makes it go through (5, 8), so it will be ...

  3x -y = 3(5) -(8)

  3x -y = 7

__

(b) The perpendicular line will have coefficients for x and y swapped and one of them negated. Again, the constant is chosen to make it go through (5, 8).

  x + 3y = (5) +3(8)

  x + 3y = 29

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If (4,5) is on the graph of a function what is the equation
Artist 52 [7]

Answer:

4 × 5 = 20

Step-by-step explanation:

Imagine this: the X is 4 and the Y is 5.

You want to find the area of it, so the equation would be

4 × 5 = 20

HOPE THIS WAS HELPFUL!!!!

3 0
3 years ago
Twenty seven pears are packed in bags of three. Five bags of pears are sold. How many pears are left
aliya0001 [1]

Answer:

Pears\ Left = 12

Step-by-step explanation:

Given

Pears = 27

Bags\ Sold = 5

Required

Determine the number of bags sold

First, we need to determine the number of bags for 27 pears;

Since they are packed in 3s

Bags = 27/3

Bags = 9

Hence:

9 bags were used for 27 pears;

After 5 bags were sold, we have:

Bags\ Left = 9 - 5

Bags\ Left = 4

Recall that the pears are packed in 3s

So:

Pears\ Left = 4 * 3

Pears\ Left = 12

4 0
4 years ago
(-2 1/2) to the second power
trapecia [35]

Answer:

6.25

Step-by-step explanation:

(-2\frac{1}{2})^2\\\\(-\frac{5}{2} )^2\\\\(\frac{5}{2})^2\\\\\frac{5^2}{2^2}\\\\\frac{25}{4}\\\\\boxed{6\frac{1}{4}}\text{ or } 6.25

Hope this helps.

5 0
3 years ago
Read 2 more answers
Which blood type was donates by the largest percent of people?
sergeinik [125]
The answer is o+ Hope this helped.
4 0
4 years ago
A store sells candy at $.50, $1, $1.50, $2, and $3 per kilogram. You can see that the unit price of candies and the amount of ca
Alecsey [184]

Answer:

Constant of variation = 3

Step-by-step explanation:

Given that a store is selling different candies costing  $.50, $1, $1.50, $2, and $3 per kilogram.

As given

Amount available to buy candies = $ 3

Suppose

Unit price of candies = x

Number of candies bough = y

Constant of variation = k

As we know the unit price of candies and number of candies bought vary inversely. As the unit price would increase the the number of candies bought in available amount ($3) would decrease.

So our formula to calculate formula for constant of variation would be as shown below:

k= xy →(1

Case 1

if we take unit price x to be $0.5, then we can buy 6 kg of candies in $ 3. In this case constant of variation can be found from above equation (1) as follows:

k = (0.5)(6) = 3

Case 2

if we take unit price x to be $1, then we can buy 3 kg of candies in $ 3. In this case constant of variation can be found from above equation (1) as follows:

k = (1)(3) = 3

Case 3

if we take unit price x to be $1.5, then we can buy 2 kg of candies in $ 3. In this case constant of variation can be found from above equation (1) as follows:

k = (1.5)(2) = 3

Case 4

if we take unit price x to be $2, then we can buy 1.5 kg of candies in $ 3. In this case constant of variation can be found from above equation (1) as follows:

k = (2)(1.5) = 3

Case 4

if we take unit price x to be $3, then we can buy 1 kg of candies in $ 3. In this case constant of variation can be found from above equation (1) as follows:

k = (3)(1) = 3

So, our constant of variation is 3.

4 0
4 years ago
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