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Lady_Fox [76]
4 years ago
13

A store sells candy at $.50, $1, $1.50, $2, and $3 per kilogram. You can see that the unit price of candies and the amount of ca

ndies that $3 buy vary inversely. What is the constant of variation?
Mathematics
1 answer:
Alecsey [184]4 years ago
4 0

Answer:

Constant of variation = 3

Step-by-step explanation:

Given that a store is selling different candies costing  $.50, $1, $1.50, $2, and $3 per kilogram.

As given

Amount available to buy candies = $ 3

Suppose

Unit price of candies = x

Number of candies bough = y

Constant of variation = k

As we know the unit price of candies and number of candies bought vary inversely. As the unit price would increase the the number of candies bought in available amount ($3) would decrease.

So our formula to calculate formula for constant of variation would be as shown below:

k= xy →(1

Case 1

if we take unit price x to be $0.5, then we can buy 6 kg of candies in $ 3. In this case constant of variation can be found from above equation (1) as follows:

k = (0.5)(6) = 3

Case 2

if we take unit price x to be $1, then we can buy 3 kg of candies in $ 3. In this case constant of variation can be found from above equation (1) as follows:

k = (1)(3) = 3

Case 3

if we take unit price x to be $1.5, then we can buy 2 kg of candies in $ 3. In this case constant of variation can be found from above equation (1) as follows:

k = (1.5)(2) = 3

Case 4

if we take unit price x to be $2, then we can buy 1.5 kg of candies in $ 3. In this case constant of variation can be found from above equation (1) as follows:

k = (2)(1.5) = 3

Case 4

if we take unit price x to be $3, then we can buy 1 kg of candies in $ 3. In this case constant of variation can be found from above equation (1) as follows:

k = (3)(1) = 3

So, our constant of variation is 3.

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NikAS [45]

The solution for s in the given equation is s = C-nD

The question seems to be incomplete

Here is the complete question:

Solve for s in this equation D= \frac{C-s}{n}   Depreciation.

To solve for s, that means we should make s the subject of the equation

From the given equation,

D= \frac{C-s}{n}

To solve for s, first multiply both sides by n to clear the fraction

We get

n\times D= n \times \frac{C-s}{n}

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Now, add s to both sides

nD + s= C - s+s

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∴ s = C-nD

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Learn more here: brainly.com/question/21406377

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. Could someone please explain this to me in detail. I am very confused. Thank you so much!. . A candle is 17 inches tall after
andrew-mc [135]

The generic equation of the line is:

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Substituting values we have:

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3 years ago
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1/4x + 1 + 3/4c - 2/3 - 1/2x<br><br> what is it equal to??
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Answer: -1/4x+1/3+3/4c

Step-by-step explanation:

<h2>We can't solve it but we can simplify</h2>
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Answer:

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Where L is the intensity in which the events happen in a time unit and x is the number of events.

To solve the problem we must calculate the probability of events  (to send 5 letters) in a unit of time for both methods, so:

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