For the lunch it would be 20$
$55-$35=20
$20 divide by $0.25=80 miles.
therefore denise can drive the car for 1day 80 miles to stay within her budget
First, it depends how you want to solve the system. The easiest way is to solve by elimination. Eliminate the 2 s. Therefore, 4x = 8. Divide by 4 to find x. After dividing by 4, x=2. To find the y plug in 2 for x in the original equation. Try for the first one. 2 +2y =3. Subtract 2 from both sides of the equation. Then you get 2y =1. Divide by 2 in both sides and you get y = 1/2.
C = 2m^2 + m
D = 2 - 6m + 2m^2
2C = 2(2m^2 + m) = 4m^2+2m
2D = 2(2-6m+2m^2) = 4-12m+4m^2
2C - 2D =
4m^2+2m-(4-12m+4m^2) =
4m^2+2m-4+12m-4m^2 =
0m^2 + 14m -4 =
14m - 4
9-3(2+6)/6-2x5
9-3x8/6-2x5
9-3x8/6-10
9-4-10
the answer is -5
