Answer18:
The quadrilateral ABCD is not a parallelogram
Answer19:
The quadrilateral ABCD is a parallelogram
Step-by-step explanation:
For question 18:
Given that vertices of a quadrilateral are A(-4,-1), B(-4,6), C(2,6) and D(2,-4)
The slope of a line is given m=
Now,
The slope of a line AB:
m=
m=
m=
The slope is 90 degree
The slope of a line BC:
m=
m=
m=
The slope is zero degree
The slope of a line CD:
m=
m=
m=
The slope is 90 degree
The slope of a line DA:
m=
m=
m=
m=
The slope of the only line AB and CD are the same.
Thus, The quadrilateral ABCD is not a parallelogram
For question 19:
Given that vertices of a quadrilateral are A(-2,3), B(3,2), C(2,-1) and D(-3,0)
The slope of a line is given m=
Now,
The slope of a line AB:
m=
m=
m=
The slope of a line BC:
m=
m=
m=
m=3
The slope of a line CD:
m=
m=
m=
The slope of a line DA:
m=
m=
m=3
The slope of the line AB and CD are the same
The slope of the line BC and DA are the same
Thus, The quadrilateral ABCD is a parallelogram
Answer:
The number of gallons of gas Karl used is 15 gallons.
Option (C) is correct.
Step-by-step explanation:
As given
Karl drove 617.3 miles.
For each gallon of gas, the car can travel 41 miles.
i.e
1 gallons = 41 miles

Now find out for the 617.3 miles.
Thus



Therefore the number of gallons of gas Karl used is 15 gallons.
Option (C) is correct.
20.6 divided by 9.7 is 2.12371134
Answer:
x = 5
Step-by-step explanation:
x + 5 =
{Midpoint theorem}
2(x+ 5) = x² - x
2x + 10 = x² - x
x² - x - 2x - 10 = 0
x² - 3x - 10 = 0
x² - 5x + 2x - (5*2) = 0
x(x - 5) + 2(x - 5) = 0
(x -5)(x + 2) = 0
{x + 2 is ignored because measurement could not be in negative value}
x - 5 = 0
x = 5