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Nataliya [291]
3 years ago
15

Which equation represents a line that has a slope of 4 and a y-intercept of 5?

Mathematics
1 answer:
Digiron [165]3 years ago
7 0
Y=4x+5 would be the equation.
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Find the uncertainty in a calculated average speed from the measurements of distance and time. Average speed depends on distance
zzz [600]

Answer:

\frac{\Delta v}{v}=0.426

Step-by-step explanation:

you have that the average sped is given by the following formula:

v(x,t)=\frac{x}{t}

The uncertainty formula for a division is given by:

\frac{\Delta v}{v}=\sqrt{(\frac{\Delta x}{x})^2+(\frac{\Delta t}{t})^2}        (1)

Δv: uncertainty in speed

Δx: uncertainty in the distance = 0.9m

Δt: uncertainty in time = 0.7s

x: distance = 8.1m

t: time = 1.7s

You replace the values of all parameters in the equation (1):

\frac{\Delta v}{v}=\sqrt{(\frac{0.9}{8.1})^2+(\frac{0.7}{1.7})^2}\\\\\frac{\Delta v}{v}=0.426

Hence, the relation between the uncertainty in the average velocity is 0.426

4 0
3 years ago
Can anyone help with any of these subjescts
Vadim26 [7]
Classify real numbers i can possibly help with! hmu! ill help
7 0
3 years ago
What is the prime number ot 35,69,89,90
Paladinen [302]
The prime number will be 69 and 89
3 0
3 years ago
suppose your average, after taking 4 quizzes is 70 out of 100. what must your average be on the next 4 quizzes to increase your
exis [7]

Answer:

94

Step-by-step explanation:

Average = Total / Number of Data

70 \times 4 = 280

You have a total of 280 points after 4 quizzes.

4+4=8 quizzes in total

Total you need for average to be 82

82 \times 8 = 656

Number of points you need to hit required:

656 - 280 = 376

You need 376 points in total for the next 4 quizzes.

376  \div 4 = 94

You need an average of 94 points on the next 4 quizzes.

5 0
3 years ago
A certain isotope decays so that the amount A remaining after t years is given by:
pashok25 [27]

f(h(x))= 2x -21

Step-by-step explanation:

f(x)= x^3 - 6

h(x)=\sqrt[3]{2x-15}

WE need to find f(h(x)), use composition of functions

Plug in h(x)

f(h(x))=f(\sqrt[3]{2x-15})

Now we plug in f(x) in f(x)

f(h(x))=f(\sqrt[3]{2x-15})=(\sqrt[3]{2x-15})^3 - 6

cube and cube root will get cancelled

f(h(x))= 2x-15 -6= 2 x-21

3 0
3 years ago
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