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devlian [24]
2 years ago
7

An average swimming pool contains 19200 gallons of water. The pool needs drained at the end of the summer. Water drains from the

pool at the rate of 12 gallons per minute.
Which equation can be used to find the volume, V, of the water in the pool m minutes after draining begins?

Mathematics
1 answer:
erastovalidia [21]2 years ago
5 0

An average swimming pool contains 19200 gallons of water. The pool needs drained at the end of the summer. Water drains from the pool at the rate of 12 gallons per minute.

Which equation can be used to find the volume, V, of the water in the pool m minutes after draining begins?An average swimming pool contains 19200 gallons of water. The pool needs drained at the end of the summer. Water drains from the pool at the rate of 12 gallons per minute.

Which equation can be used to find the volume, V, of the water in the pool m minutes after draining begins?An average swimming pool contains 19200 gallons of water. The pool needs drained at the end of the summer. Water drains from the pool at the rate of 12 gallons per minute.

Which equation can be used to find the volume, V, of the water in the pool m minutes after draining begins?An average swimming pool contains 19200 gallons of water. The pool needs drained at the end of the summer. Water drains from the pool at the rate of 12 gallons per minute.

Which equation can be used to find the volume, V, of the water in the pool m minutes after draining begins?An average swimming pool contains 19200 gallons of water. The pool needs drained at the end of the summer. Water drains from the pool at the rate of 12 gallons per minute.

Which equation can be used to find the volume, V, of the water in the pool m minutes after draining begins?

61y)6y \times 2 \div  \sqrt[ \geqslant  | | \frac{ >  >  <  =  {348)48)98)8(978). >  \\  | >  | \sqrt[m \: \% log( \beta  \tan( \\  log_{ log_{ \binom{ \\  \\ {}cbc log(\pi \beta  \sec( \cos( \tan( \sin( \infty e log( ln( log( ln( > .15 - 756 { >  | >  | <  \sqrt[ < 5x6y6)9x9yyyy \div  \frac{ \\ 2697930046y - xy >  \geqslant \:  \binom{ log( \binom{ \sec( \gamma  \\ }m{cx > 03y9)y \times ) }{?} ) }{?}  \times \frac{?}{?} }{?}  \times \frac{?}{?} ]{?} | | }^{?} ) ) ) ) ) ) ) ) ) }{?} }(?) }(?) ) ) ]{?} | | }^{?} }{?} | | ]{?}

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Answer:

x = a/(a² + b²) or x = -1/a  

Step-by-step explanation:

a(a²+ b²)x² + b²x - a =0

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x = \dfrac{-b\pm\sqrt{b^2-4ac}}{2a} =\dfrac{-b\pm\sqrt{D}}{2a}

1. Evaluate the discriminant D

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2. Solve for x

\begin{array}{rcl}x & = & \dfrac{-b\pm\sqrt{D}}{2a}\\\\ & = & \dfrac{-b^{2}\pm\sqrt{(b^{2}+2a^{2})^{2}}}{2a(a^{2} + b^{2})}\\\\ & = & \dfrac{-b^{2}\pm(b^{2}+ 2a^{2})}{2a(a^{2} + b^{2})}\\\\x = \dfrac{-b^{2}+(b^{2} + 2a^{2})}{2a(a^{2} + b^{2})}&\qquad& x =\dfrac{-b^{2}-(b^{2} + 2a^{2})}{2a(a^{2} + b^{2})}\\\\x =\dfrac{-b^{2}+(b^{2} + 2a^{2})}{2a(a^{2} + b^{2})}&\qquad& x =\dfrac{-b^{2}-(b^{2} +2a^{2})}{2a(a^{2} + b^{2})}\\\\\end{array}

\begin{array}{rcl}x = \large \boxed{\mathbf{\dfrac{a}{a^{2} + b^{2}}}}&\qquad& x =\dfrac{-b^{2}-(b^{2} +2a^{2})}{2a(a^{2} + b^{2})}\\\\&\qquad& x =\dfrac{-2b^{2}- 2a^{2}}{2a(a^{2} + b^{2})}\\\\&\qquad& x =\dfrac{-2(a^{2}+ b^{2})}{2a(a^{2} + b^{2})}\\\\&\qquad& x =\large \boxed{\mathbf{-\dfrac{1}{a}}}\\\\\end{array}

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Elodia [21]

Answer:

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Step-by-step explanation:

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3 years ago
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a group of friends are hiking on trail y when they reach an intersection with trail x. Trail x is perpendicular to trail y. If t
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Need help with 3 and 4 consumer math plz
ratelena [41]

Answer:

3) C) $792.50

4) D) $707.50

Step-by-step explanation:

3) Home price = $ 253,600

Mortgage rate = 3.75% APR

Therefore, monthly rate = 3.75% divide by 12

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Principal paid in the first month = 1500 - 792.50

= $707.50

Answer: D) $707.50

Thank you.

6 0
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