<h3>
Answer:</h3>
- 32 kg of 30% copper
- 48 kg of 55% copper
<h3>
Step-by-step explanation:</h3>
Let x represent the mass of 55% copper alloy that is to be used in the mix. Then 80-x is the mass of 30% copper alloy to be used. The total amount of copper in the mix is then ...
... 0.55x + 0.30(80-x) = 0.45·80
... 0.25x = 12 . . . . . . simplify, subtract 24
... x = 48 . . . . . . . . . divide by the coefficient of x
... 80-x = 32 . . . . . . the mass of 30% copper alloy required
The metalworker should combine 32 kg of 30% copper alloy with 48 kg of 55% copper alloy to make 80 kg of 45% copper alloy.
Part a: 21 dollars because you multiply .40 with 5 and get 6. you add the 6 to the 15 and get 21.
part b: 30.21 because you multiply 38 by .25 and get the answer for that and then subtract that number from 38. then you multiply 0.06 by 38 and when u get that number, add that to the discounted price.
M<NQN = 180° - 2[180° - (60° + 80°)]
m<NQM = 100°
~100°
