1. A (3,6) = (1,9) B(-1,2) = (-3,5) C (1,-4) = (-1,-1) 2. K (5,7) = (-1,7) L (3,7) = (1,7) M (3,5) = (1,5) N (6,4) = (-2,4) 3. Q (5,-8) = (5,8) R(5,-4) = (5,4) S (2,-4) = (2,4) T (2,-8) = (2,8) I believe those are the correct points. I hope this helps :D
A (3,6) = (1,9) B(-1,2) = (-3,5) C (1,-4) = (-1,-1) 2. K (5,7) = (-1,7) L (3,7) = (1,7) M (3,5) = (1,5) N (6,4) = (-2,4) 3. Q (5,-8) = (5,8) R(5,-4) = (5,4) S (2,-4) = (2,4) T (2,-8) = (2,8) I believe those are the correct points. I hope this helps :D
Use the identity sec^2x = 1 + tan^2 x - so sec x = sqrt(1 + tan^2 x) then:- tan x + sqrt( 1 + tan^2 x) = 1 sqrt ( 1 + tan^2 x) = 1 - tan x 1 + tan^2 x = 1 + tan^2x - 2 tan x 0 = -2 tanx
tan x = 0
x = 0, π π is an extraneous root because sec 180 = -1 So the answer is 0 degrees