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Korolek [52]
3 years ago
15

{8} ⊆ {7,8,9} true or false

Mathematics
2 answers:
Natalija [7]3 years ago
6 0

the answer is false

.....................................

Triss [41]3 years ago
6 0

Answer:

Homework #1-18: Answer yes or no, if no give the reason

1) Is A ⊆ B given A = silver, B = {gold, silver, diamond}

A is not a set, so it can’t be a proper subset.

Answer: no, because A is not a set

3) Is C ⊆ D given C = {Phoenix}, D = {Phoenix, Glendale, Peoria, Scottsdale}

I need two rules to work.

C is a set so rule 1 is satisfied.

Every element of C is also an element of D, so rule 2 is satisfied.

Answer: yes

5) Is A ⊆ B given A = {2,3} , B = {1,2,3,4,5}

I need two rules to work.

A is a set so rule 1 is satisfied.

Every element of A is also an element of B, so rule 2 is satisfied.

Answer: yes

7) Is A ⊆ B given A = a, B = {| }

A is not a set, so it can’t be a proper subset.

Answer: no, because A is not a set

9) Is A ⊆ B given A = { }, B = {1,2,3,4,5}

Answer yes: the empty set is a subset of every set.

11) Is S ⊂ T given, S= ∅, T = {1,2,3,4,5}

Answer yes: the empty set is a subset of every set.

13) Is A ⊂ B given A = {1,2,3}, B = {3,2,1}

This is not a true statement. The sets are equal and this symbol does not allow sets to be equal.

Answer: no, sets are equal

15) Is C ⊂ D given C = {1,2,3,4,5}, D = {1,2,3,4}

Answer: no, C is not contained in D, so this is not true

17) Is A ⊂ B given A = {4,3,2,1 }, B = {1,2,3,4,5}

A is a set so rule 1 is satisfied,

A is contained in B so rule 2 is satisfied

A is not equal to B so rule 3 is satisfied

Answer: yes (all 3 rules are satisfied)

Homework #19 – 34: Determine which of these are true. (Choose every answer that is true, in

many instances there will be more than one correct choice.)

A = B, A ⊆ B, B ⊆ A, A ⊂ B, B ⊂ A, or none of these

19) A = {Trix, Captain Crunch, Rice Krispees} B = {Rice Krispees}

B is contained, but not equal to A. B is both a subset and a proper subset of A.

A is not contained in B

The sets are not equal.

Answer: B ⊆ A, B ⊂ A

Step-by-step explanation:

here all of it

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