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pochemuha
3 years ago
14

Is x^2y^2-25 a monomial, binomial, or a trinomial?

Mathematics
1 answer:
igor_vitrenko [27]3 years ago
3 0

Answer:

trinomial

Step-by-step explanation:

there are 3 terms

x^2

y^2

-25

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Help me please help posted picture of question
ira [324]

Answer:

True

Step-by-step explanation:

The natural numbers are those which allow us to count the elemnts of a set, for example: how many people are in the room or how many chairs we have, however we have infinity things to mention. Zero is not part off it, belong to Real and Complex numbers.

5 0
3 years ago
Help please i asked for this question But no one answers me :( I will give 25 points please!!
Ganezh [65]

Answer:

3 + 0.8 + 0.03 + 0.005

Step-by-step explanation:

Expand the number. Set each non-zero digit by itself:

3.835 = 3 + 0.8 + 0.03 + 0.005

3 + 0.8 + 0.03 + 0.005 is your answer.

~

5 0
3 years ago
Read 2 more answers
Let X be a binomial random variable with p = 0.7 and n = 10. Calculate the following probabilities from the binomial probability
padilas [110]

Answer:

0.4114  

0.0006  

0.1091  

0.1957  

Step-by-step explanation:

<u>Given:  </u>

p = 0.7 n = 10

We need to determine the probabilities using table , which contains the CUMULATIVE probabilities P(X \leq x).  

a. The probability is given in the row with n = 10 (subsection x = 3) and in the column with p = 0.7 of table:  

P(X \leq  3) = 0.4114  

b. Complement rule:  

P( not A) = 1 - P(A)

Determine the probability given in the row with n = 10 (subsection x = 10) and in the column with p = 0.7 of table:  

P(X \leq  10) = 0.9994

Use the complement rule to determine the probability:  

P(X > 10) = 1 - P(X\leq 10) = 1 - 0.9994 = 0.0006  

c. Determine the probability given in the row with n = 10 (subsection x = 5 and x = 6) and in the column with p = 0.7 of table:  

P(X \leq  5) = 0.8042

P(X \leq  6) = 0.9133

The probability at X = 6 is then the difference of the cumulative probabilities:  

P(X = 6) = P(X \leq  6) - P(X \leq  5) = 0.9133 — 0.8042 = 0.1091  

d. Determine the probability given in the row with n = 10 (subsection x = 5 and x = 11) and in the column with p = 0.7 of table:  

P(X \leq  5) = 0.8042

P(X \leq  11) = 0.9999

The probability at 6 \leq X \leq 11 is then the difference between the corresponding cumulative probabilities:  

P(6 \leq  X \leq 11) = P(X \leq 11) - P(X \leq  5) = 0.9999 — 0.8042 = 0.1957  

6 0
3 years ago
DUE NOW!!!
KiRa [710]

Answer:

He will be 2.6 Miles away from the canyon.

Step-by-step explanation:

4.2-1.6=2.6

5 0
3 years ago
Read 2 more answers
Look at number 17. What did I do wrong?
Gnesinka [82]
When you are checking your answers, your formula should read out as 9(2.222) - 8 = 12, which is simply filing in the x value that you calculated (it comes out to 11.998 which is correct). You wrote it out as 9(2.22) - 8 = -6, which is why your checking process was incorrect 
7 0
3 years ago
Read 2 more answers
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