Answer:
True
Step-by-step explanation:
The natural numbers are those which allow us to count the elemnts of a set, for example: how many people are in the room or how many chairs we have, however we have infinity things to mention. Zero is not part off it, belong to Real and Complex numbers.
Answer:
3 + 0.8 + 0.03 + 0.005
Step-by-step explanation:
Expand the number. Set each non-zero digit by itself:
3.835 = 3 + 0.8 + 0.03 + 0.005
3 + 0.8 + 0.03 + 0.005 is your answer.
~
Answer:
0.4114
0.0006
0.1091
0.1957
Step-by-step explanation:
<u>Given: </u>
p = 0.7 n = 10
We need to determine the probabilities using table , which contains the CUMULATIVE probabilities P(X
x).
a. The probability is given in the row with n = 10 (subsection x = 3) and in the column with p = 0.7 of table:
P(X
3) = 0.4114
b. Complement rule:
P( not A) = 1 - P(A)
Determine the probability given in the row with n = 10 (subsection x = 10) and in the column with p = 0.7 of table:
P(X
10) = 0.9994
Use the complement rule to determine the probability:
P(X > 10) = 1 - P(X
10) = 1 - 0.9994 = 0.0006
c. Determine the probability given in the row with n = 10 (subsection x = 5 and x = 6) and in the column with p = 0.7 of table:
P(X
5) = 0.8042
P(X
6) = 0.9133
The probability at X = 6 is then the difference of the cumulative probabilities:
P(X = 6) = P(X
6) - P(X
5) = 0.9133 — 0.8042 = 0.1091
d. Determine the probability given in the row with n = 10 (subsection x = 5 and x = 11) and in the column with p = 0.7 of table:
P(X
5) = 0.8042
P(X
11) = 0.9999
The probability at 6
X
11 is then the difference between the corresponding cumulative probabilities:
P(6
X
11) = P(X
11) - P(X
5) = 0.9999 — 0.8042 = 0.1957
Answer:
He will be 2.6 Miles away from the canyon.
Step-by-step explanation:
4.2-1.6=2.6
When you are checking your answers, your formula should read out as 9(2.222) - 8 = 12, which is simply filing in the x value that you calculated (it comes out to 11.998 which is correct). You wrote it out as 9(2.22) - 8 = -6, which is why your checking process was incorrect