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3 years ago

Please include step by step

Mathematics

1 answer:

mote1985 [20]3 years ago

5 0

Answer:

x=2 AB=hypotenus(h) angle ACB is 90

BC=p angle CAB is 30 also angle of refrence

Step-by-step explanation:

sin[30]=p/h

(1/2)=x/4

2x=4

x=2

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Suppose a student's score on a standardize test to be a continuous random variable whose distribution follows the Normal curve.

blsea [12.9K]

Answer:

a) Percentage of students scored below 300 is 1.79%.

b) Score puts someone in the 90th percentile is 638.

Step-by-step explanation:

Given : Suppose a student's score on a standardize test to be a continuous random variable whose distribution follows the Normal curve.

(a) If the average test score is 510 with a standard deviation of 100 points.

To find : What percentage of students scored below 300 ?

Solution :

Mean $\mu=510$ ,

Standard deviation $\sigma=100$

Sample mean $x=300$

Percentage of students scored below 300 is given by,

$P(Z\leq \frac{x-\mu}{\sigma})\times 100$

$=P(Z\leq \frac{300-510}{100})\times 100$

$=P(Z\leq \frac{-210}{100})\times 100$

$=P(Z\leq-2.1)\times 100$

$=0.0179\times 100$

$=1.79\%$

Percentage of students scored below 300 is 1.79%.

(b) What score puts someone in the 90th percentile?

90th percentile is such that,

$P(x\leq t)=0.90$

Now, $P(\frac{x-\mu}{\sigma} < \frac{t-\mu}{\sigma})=0.90$

$P(Z< \frac{t-\mu}{\sigma})=0.90$

$\frac{t-\mu}{\sigma}=1.28$

$\frac{t-510}{100}=1.28$

$t-510=128$

$t=128+510$

$t=638$

Score puts someone in the 90th percentile is 638.

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3 years ago

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Snezhnost [94]

Answer:

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Step-by-step explanation:

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3 years ago

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zimovet [89]

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Step-by-step explanation:

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3 years ago

Read 2 more answers

Find the length of AB?

vampirchik [111]

Given:

The figure of a right triangle.

To find:

The length of AB.

Solution:

In a right angle triangle,

$\cos \theta=\dfrac{Base}{Hypotenuse}$

Using this trigonometric ratio for the given triangle, we get

$\cos A=\dfrac{AB}{AC}$

$\cos (60^\circ)=\dfrac{AB}{10}$

$\dfrac{1}{2}=\dfrac{AB}{10}$

$\dfrac{1}{2}\times 10=AB$

$5=AB$

Therefore, the length of AB is 5 units.

7 0

3 years ago