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LenKa [72]
3 years ago
6

Help me, I need it so bad... I only have 20 minutes!

Mathematics
1 answer:
Arada [10]3 years ago
7 0

s=200

b=100

1.08 s + 1.02 b = 1.08(200) + 1.02(100) = 216 + 102 = 318

Answer: 318


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What is the slope of the line represented by the following equation​
Lapatulllka [165]

Answer:

D 2

Step-by-step explanation:

hope this helps you

5 0
2 years ago
What are the next 3 numbers in this sequence? 1,1,2,4,7,13,24,44
Bogdan [553]
81,149, 274.... adding three numbers from the last would help you

like if you take 7 = 4 + 2 +1

or 13 = 7 + 4 +2

similarly 44+24+13 = 81
              81+44 +24 = 149
              149 + 81 +44 = 274

hope you get it!

6 0
3 years ago
A worker at a cabinet shop is cutting out pieces of wood for a dresser. He needs pieces that are 4 1/4inches long. Each saw cut
ella [17]

Answer: he will be able to make 19 full pieces

Step-by-step explanation:

1. Start off by making 7 feet into 84 inches so the measurements can match.

2. Add 4/14 inches and the 1/8 a inch together so you know how much is being taken off 84 inches. The amount will be 35/8 inches.

3. Divide 84 inches by 35/8 inches = 19 1/5

4. The whole number of the answer will be how many boards you can make from the board.

8 0
2 years ago
"Suppose an object falling in the atmosphere has mass m=15kg and the drag coefficient is γ=9kg/s. Recall that the differential e
Art [367]

Answer:

a. v(t)= -6.78e^{-16.33t} + 16.33 b. 16.33 m/s

Step-by-step explanation:

The differential equation for the motion is given by mv' = mg - γv. We re-write as mv' + γv = mg ⇒ v' + γv/m = g. ⇒ v' + kv = g. where k = γ/m.Since this is a linear first order differential equation, We find the integrating factor μ(t)=e^{\int\limits^  {}k \, dt } =e^{kt}. We now multiply both sides of the equation by the integrating factor.

μv' + μkv = μg ⇒ e^{kt}v' + ke^{kt}v = ge^{kt} ⇒ [ve^{kt}]' = ge^{kt}. Integrating, we have

∫ [ve^{kt}]' = ∫ge^{kt}

    ve^{kt} = \frac{g}{k}e^{kt} + c

    v(t)=   \frac{g}{k} + ce^{-kt}.

From our initial conditions, v(0) = 9.55 m/s, t = 0 , g = 9.8 m/s², γ = 9 kg/s , m = 15 kg. k = y/m. Substituting these values, we have

9.55 = 9.8 × 15/9 + ce^{-16.33 * 0} = 16.33 + c

       c = 9.55 -16.33 = -6.78.

So, v(t)=   16.33 - 6.78e^{-16.33t}. m/s = - 6.78e^{-16.33t} + 16.33 m/s

b. Velocity of object at time t = 0.5

At t = 0.5, v = - 6.78e^{-16.33 x 0.5} + 16.33 m/s = 16.328 m/s ≅ 16.33 m/s

6 0
2 years ago
PLZ HELP ME IT IS VERY URGENT THERE ARE three QUESTIONS PLZ ANSWER THEM!!
Mice21 [21]

Answer:

133, B and C

Step-by-step explanation:

3 0
3 years ago
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