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rusak2 [61]
2 years ago
6

Jessica has been tracking the population of a town. The population was 8,230 last year and has been increasing by 1.25 times eac

h year. How can Jessica develop a function to model this?
f(x) = (8230 ⋅ 1.25)x where 1.25 is the rate of growth

f(x) = 8230(1.25)x where 1.25 is the rate of growth

f(x) = 1.25(8230)x where 8230 is the rate of growth

f(x) = 8230(x)1.25 where 8230 is the rate of growth
Mathematics
1 answer:
marusya05 [52]2 years ago
7 0
Initial population = 8230

The population is:
After 1 year, 8230(1.25)¹
After 2 years, 8230(1.25)²
 ...
After x years, 8230(1.25)ˣ

The population after x years is
f(x) = 8230 (1.25)ˣ

Answer:  8230(1.25)ˣ, where 1.25 is the rate of growth.
The second answer is correct.
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The stock's value dropped from $38.50 to $34.00.What negative number shows the change in value?
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$-4.50 change in value
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Freddy went to the museum and bought a reduced copy of a painting he saw in a exhibit. If the actual painting is 12 inches high,
Snowcat [4.5K]

Answer:

It is probably 6 inches wide. I tried my best

Step-by-step explanation:

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2 years ago
Find , , and if and terminates in quadrant .
ioda

sin2x =12/13

cos2x = 5/13

tan2x = 12/5

STEP - BY - STEP EXPLANATION

What to find?

• sin2x

,

• cos2x

,

• tan2x

Given:

tanx = 2/3 = opposite / adjacent

We need to first make a sketch of the given problem.

Let h be the hypotenuse.

We need to find sinx and cos x, but to find sinx and cosx, first determine the value of h.

Using the Pythagoras theorem;

hypotenuse² = opposite² + adjacent²

h² = 2² + 3²

h² = 4 + 9

h² =13

Take the square root of both-side of the equation.

h =√13

This implies that hypotenuse = √13

We can now proceed to find the values of ainx and cosx.

Using the trigonometric ratio;

\sin x=\frac{opposite}{\text{hypotenuse}}=\frac{2}{\sqrt[]{13}}\cos x=\frac{adjacent}{\text{hypotenuse}}=\frac{3}{\sqrt[]{13}}

And we know that tanx =2/3

From the trigonometric identity;

sin 2x = 2sinxcosx

Substitute the value of sinx , cosx and then simplify.

\sin 2x=2(\frac{2}{\sqrt[]{13}})(\frac{3}{\sqrt[]{13}})=\frac{12}{13}

Hence, sin2x = 12/13

cos2x = cos²x - sin²x

Substitute the value of cosx, sinx and simplify.

\begin{gathered} \cos 2x=(\frac{3}{\sqrt[]{13}})^2-(\frac{2}{\sqrt[]{13}})^2 \\  \\ =\frac{9}{13}-\frac{4}{13} \\ =\frac{5}{13} \end{gathered}

Hence, cos2x = 5/13

tan2x = 2tanx / 1- tan²x

\tan 2x=\frac{2\tan x}{1-\tan ^2x}=\frac{2(\frac{2}{3})}{1-(\frac{2}{3})^2}=\frac{\frac{4}{3}}{1-\frac{4}{9}}=\frac{\frac{4}{3}}{\frac{9-4}{9}}=\frac{\frac{4}{3}}{\frac{5}{9}}=\frac{4}{3}\times\frac{9}{5}=\frac{4}{1}\times\frac{3}{5}=\frac{12}{5}

OR

\tan 2x=\frac{\sin 2x}{\cos 2x}=\frac{\frac{12}{13}}{\frac{5}{13}}=\frac{12}{5}

Hence, tan2x = 12/5

Therefore,

sin2x =12/13

cos2x = 5/13

tan2x = 12/5

3 0
1 year ago
one rectangle measures 2 units by 7 units. a second rectangle measures 11 units by 37 units. are these two figures scaled versio
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Answer: The both triangle are not scale version to each other.

Explanation:

It is given that the one rectangle measures 2 units by 7 units. a second rectangle measures 11 units by 37 units.

The two shapes are scaled version of each other if their corresponding sides are in same proportion. In other words the if two shapes scaled version of each then the shapes are similar.

The sides or first rectangle are 2 and 7. The measures of second rectangle are 11 and 37.

The proportion of small side is,

\frac{2}{11}

The proportion of large side is,

\frac{7}{37}

So,

\frac{2}{11}\neq \frac{7}{37}

Since the proportion are not equal, therefore  both triangle are not scale version to each other.

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Answer:

I snsmxxabrsgfbsseg

Step-by-step explanation:

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