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rusak2 [61]
3 years ago
6

Jessica has been tracking the population of a town. The population was 8,230 last year and has been increasing by 1.25 times eac

h year. How can Jessica develop a function to model this?
f(x) = (8230 ⋅ 1.25)x where 1.25 is the rate of growth

f(x) = 8230(1.25)x where 1.25 is the rate of growth

f(x) = 1.25(8230)x where 8230 is the rate of growth

f(x) = 8230(x)1.25 where 8230 is the rate of growth
Mathematics
1 answer:
marusya05 [52]3 years ago
7 0
Initial population = 8230

The population is:
After 1 year, 8230(1.25)¹
After 2 years, 8230(1.25)²
 ...
After x years, 8230(1.25)ˣ

The population after x years is
f(x) = 8230 (1.25)ˣ

Answer:  8230(1.25)ˣ, where 1.25 is the rate of growth.
The second answer is correct.
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Answer:

Similarly, the distance between two points P1 = (x1,y1,z1) and P2 = (x2,y2,z2) in xyz-space is given by the following generalization of the distance formula, d(P1,P2) = (x2 x1)2 + (y2 y1)2 + (z2 z1)2. This can be proved by repeated application of the Pythagorean Theorem.

Step-by-step explanation:

Use a calculator  

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3 years ago
The shape of the distribution of the time required to get an oil change at a 10 minute oil change facility is unknown. However,
lyudmila [28]

Answer:

The answer is below

Step-by-step explanation:

a) For a normal model the sample size has to be equal or greater than 30 so that it can be a normal distribution.

b) Given that:

μ = 11.2 minutes, σ = 4.8 minutes, n = 45

The z score determines how many standard deviations the raw score is above or below the mean. It is given by:

z=\frac{x-\mu}{\sigma} \\For\ a\ sample\ size(n)\\z=\frac{x-\mu}{\sigma/\sqrt{n} }

For x < 10 minutes

z=\frac{x-\mu}{\sigma/\sqrt{n} }\\\\ z=\frac{10-11.2}{4.8/\sqrt{45} }= -1.68

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7 0
3 years ago
Complete the comparison: 26 &lt;
EastWind [94]
26< any number larger than 26 (whole numbers and fractions/decimals)
6 0
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What is 17,574 in expanded form?
NikAS [45]

Answer:

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Step-by-step explanation:

8 0
3 years ago
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What are the first three terms of the sequence...plz help pt.1​
svetlana [45]

a_{n} \:  =  \: 2(a_{n - 1})^{2} \\ a_{1} = 4 \: (given) \\ a_{2} = \: 2(a_{2 - 1})^{2}  \\  = 2(a_{ 1})^{2}   \\  = 2 \times  {4}^{2}  \\  = 32 \\  \\ a_{3} = \: 2(a_{3 - 1})^{2}  \\  = 2(a_{ 2})^{2}   \\  = 2 \times  {32}^{2}  \\  = 2 \times 1024 \\  = 2048

so first 3 terms are

4, 32, 2048

8 0
3 years ago
Read 2 more answers
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