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Ratling [72]
3 years ago
6

Identify sin Y as a fraction and as a decimal rounded to the nearest hundredth. Help please!!

Mathematics
1 answer:
Lina20 [59]3 years ago
5 0

sine=\dfrac{opposite}{hypotenuse}

We have

opposite7.4\\hypotenuse=10.9

Substitute:

\large\boxed{\sin Y=\dfrac{7.4}{10.9}\approx0.68}

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1/3x^2 by -2/9x divide it ​
Lana71 [14]
The answer is -3x^3/2
6 0
2 years ago
HELP ME ITS SO EASY BUT I NEED HELP
Naddika [18.5K]

Answer:

7.2111(4 decimal places)

Step-by-step explanation:

a squared by b squared=c squared

36 + 16 is 52, so then you need to square root 52 which is 7.2111 to 4 decimal places. I hope you benefit from this. Cheers

5 0
2 years ago
Find d for the arithmetic series with S17=-170 and a1=2
Irina18 [472]
So, we know the sum of the first 17 terms is -170, thus S₁₇ = -170, and we also know the first term is 2, well

\bf \textit{ sum of a finite arithmetic sequence}\\\\
S_n=\cfrac{n(a_1+a_n)}{2}\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
----------\\
n=17\\
S_{17}=-170\\
a_1=2
\end{cases}
\\\\\\
-170=\cfrac{17(2+a_{17})}{2}\implies \cfrac{-170}{17}=\cfrac{(2+a_{17})}{2}
\\\\\\
-10=\cfrac{(2+a_{17})}{2}\implies -20=2+a_{17}\implies -22=a_{17}

well, since the 17th term is that much, let's check what "d" is then anyway,

\bf n^{th}\textit{ term of an arithmetic sequence}\\\\
a_n=a_1+(n-1)d\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
d=\textit{common difference}\\
----------\\
n=17\\
a_{17}=-22\\
a_1=2
\end{cases}
\\\\\\
-22=2+(17-1)d\implies -22=2+16d\implies -24=16d
\\\\\\
\cfrac{-24}{16}=d\implies -\cfrac{3}{2}=d
6 0
3 years ago
Someone plz help me I will give brainliest
makvit [3.9K]

Answer:

2. 3/4 x 5/9 = 3x5/4x9 = 15/36 = 5/12

4. 4/7 x 1/2 = 4x1/7x2 = 4/14 = 2/7

6. 4/9 x 2/3 = 4x2/9x3=8/27

Step-by-step explanation:

Hope it helps!

5 0
3 years ago
Read 2 more answers
What is the coefficient of X^2Y^2 in the expansion of (x+y)^4
nata0808 [166]

Answer:

6

Step-by-step explanation:

We want to expand this; (x + y)⁴

This can be written as;

(x + y)² × (x + y)²

This gives;

(x² + 2xy + y²) × (x² + 2xy + y²)

This gives;

x²(x² + 2xy + y²) + 2xy(x² + 2xy + y²) + y²(x² + 2xy + y²) = x⁴ + 2x³y + x²y² + 2x³y + 4x²y² + 2xy³ + x²y² + 2xy³ + y⁴

Simplifying gives;

x⁴ + 4x³y + 4xy³ + 6x²y² + y⁴

Thus, the coefficient of x²y² is 6

3 0
2 years ago
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