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AVprozaik [17]
2 years ago
14

Escreva na forma ax2+bx+c=0 as seguintes equações do 2° grau

Mathematics
1 answer:
7nadin3 [17]2 years ago
3 0
The answer is 2x(5+3)
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find a number such that if 8 is subtracted from 9 times the number , the result is 6 more than twice the number​
zheka24 [161]

Answer:

x=2

Step-by-step explanation:

let the number be x

9x-8=6+2x

9x-2x=6+8

7x=14

x=14/7

x=2

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3 years ago
How do I solve this question?
Juli2301 [7.4K]

11 because if you count the spaces between the two places, the answer would be 11.

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0.3 x 2075. Use a calculator.
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2 years ago
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8x^-9+(-3x^-3y-2)(5/x^6y-2)
DaniilM [7]

8x^{-9}+(-3x^{-3}y^{-2})(\frac{5}{x^6y^{-2}})

the first step is to deal with the negative exponents, which causes numbers to go to the other side of the fraction

8x^{-9}+(-3x^{-3}y^{-2})(\frac{5}{x^6y^{-2}})

goes to

\frac{8}{x^9}+(\frac{-3}{x^3y^2})(\frac{5y^2}{x^6})

now we can simplify the multiplied terms

\frac{8}{x^9}+(\frac{-15}{x^9})

Now that we have common bases, we can add the 2 fractions together to get

\frac{-7}{x^9}

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A.) 2, 7

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