Since sine of all angles are always less than one, this shows there is no possible way to have an angle C. Thus it is impossible to have a triangle ABC with the given properties of side lengths b=3 inches and c= 5 inches to have angle B =45 degrees.

Step-by-step explanation:

In the attached drawing, each of the tic-marks are equal and

represent 1 inch each. The angle B has measure 45. We can

see by the arc that the line AC, which equals 3 inches, is

not long enough to reach the slanted side of the 45 angle.

Therefore triangle ABC is not possible. We can also show

by the law of sines that no triangle ABC with the given

properties in possible.

5 0

3 years ago

How to factorised quadratics in simple form thank you

photoshop1234 [79]

Answer:

ax²+ bx + c = 0

Step-by-step explanation

Multiplying (x+4) and (x−1) together (called Expanding) gets x2 + 3x − 4 :

expand vs factor quadratic

So (x+4) and (x−1) are factors of x2 + 3x − 4

Just to be sure, let us check:

(x+4)(x−1) = x(x−1) + 4(x−1)

= x2 − x + 4x − 4

= x2 + 3x − 4 yes

Yes, (x+4) and (x−1) are definitely factors of x2 + 3x − 4

6 0

3 years ago

I need help with this

daser333 [38]

Answer:

Step-by-step explanation:

Please mark me brainliest

7 0

2 years ago