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DaniilM [7]
3 years ago
7

(8,-7)m=-3/4 write an equation in point slope form of the line that passes through the given point and has the given slope

Mathematics
1 answer:
Paladinen [302]3 years ago
6 0

Answer:

Equation of the straight line in point-slope form

 y -(-7) = \frac{-3}{4}(x-8)

Equation of the straight line

3x +4y +4=0

Step-by-step explanation:

<u><em>Explanation:-</em></u>

Given that the point ( 8,-7) and  m = \frac{-3}{4}

Equation of the straight line passing through the point (x₁, y₁) and having slope 'm'

          y - y₁ = m (x-x₁)

        y -(-7) = \frac{-3}{4}(x-8)

       4( y+7) = -3(x-8)

       4y +28 = -3x +24

      3x +4y +28 -24 =0

      3x +4y +4=0

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Answer:

The calculated value     t =   2.366 > 2.0301 at 0.05 level of significance

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Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given that the first sample size 'n₁' = 22

Given that the mean of the first sample x₁⁻ = 120

Given that the standard deviation of the sample (s₁) = 20

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     where

             S^{2} = \frac{n_{1} S_{1} ^{2}+n_{2} S_{2} ^{2}   }{n_{1} +n_{2}-2 }

            S^{2} = \frac{22( 20)^{2}+ 15(30) ^{2}   }{22 +15-2 }

           S² =  637.1428

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The standard deviation of the sample 'S' = 25.24168   

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<u><em>Null Hypothesis:H₀:</em></u>

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<u><em>Alternative Hypothesis:H₁:</em></u>

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         T-test statistic

               t = \frac{x^{-} _{1} -x^{-} _{2} }{\sqrt{S^{2} (\frac{1}{n_{1} }+\frac{1}{n_{2} } ) } }

              t = \frac{ 120 -100 }{\sqrt{637.14 (\frac{1}{22 }+\frac{1}{15 } ) } }

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Degrees of freedom

           γ = n₁+n₂ -2 = 22+15-2 = 35

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The calculated value     t =   2.366 > 2.0301 at 0.05 level of significance

The null hypothesis is rejected

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