Let the width be x.
Length is 8 feet more than width. Length = x + 8
Area = x(x + 8)
width increased by 4, that is, (x + 4)
Length decreased by 5, (x + 8 - 5) = (x + 3)
Area = (x + 4)(x +3)
Area remains the same
x(x + 8) = (x+4)(x +3)
x² + 8x = x(x +3) + 4(x +3)
x² + 8x = x² +3x + 4x +12
x² + 8x = x² +7x +12 Eliminate x² from both sides
8x = 7x + 12
8x - 7x = 12
x = 12
Dimensions of original rectangle : x, x + 8
12, 12 +8 = 12, 20
Original rectangle is 20 feet by 12 feet
Im a little confused here because there isn't enough information to go on or I might be reading it wrong.
Answer:
Option B. 1.8 seconds
Step-by-step explanation:
h=-16t^2+56t+1
This is a quadratic equation, and its graph is a parabola
h=at^2+bt+c; a=-16, b=56, c=1
Like a=-16<0 the parabola opens downward, and it has a maximum value (height) at the vertex, at the abscissa:
Replacing the known values:
Approximately 1.8 seconds.
Answer: It takes approximately 1.8 seconds the airplane to reach its maximum height.
Answer:
2
Step-by-step explanation:
Let's solve the given system of equations.
<u>Given system</u>
x +3y= 10 ----(1)
-2x -2y= 4 ----(2)
From (2):
-2(x +y)= 4
Dividing both sides by -2:
x +y= -2 ----(2)
Thus, options 3 and 4 are incorrect as x +y≠ -2.
(1) -(2):
(x +3y) -(x +y)= 10 -(-2)
Expand:
x +3y -x -y= 10 +2
2y= 12
Divide both sides by 2:
y= 12 ÷2
y= 6
Substitute y= 6 into (2):
x +6= -2
x= -6 -2
x= -8
Options (1) and (2) differs only by the value of the expression of -x +y. Thus, let's find its value in the given system of equations.
-x +y
= -(-8) +6
= 8 +6
= 14
Thus, option 2 is the correct option.
