Question

Points B and B' have symmetry with respect to P. Find the coordinates of P when B is (2, 8) and B' is (2, 2). A. (2, 5) B. (0, 5) C. (5, 2)

Answer 1

Answer:

A. (2, 5)

Step-by-step explanation:

If B and B' have symmetry, then P is a midpoint between those points. We can determinate the location of point P by using the midpoint equation, whose vectorial form is:

$P(x,y) = \frac{1}{2}\cdot B(x,y)+\frac{1}{2}\cdot B'(x,y)$ (Eq. 1)

If we know that $B(x,y) = (2,8)$ and $B'(x,y) = (2,2)$, then the location of P is:

$P(x,y) = \frac{1}{2}\cdot (2,8)+\frac{1}{2}\cdot (2,2)$

$P(x,y) = (1, 4)+(1,1)$

$P(x,y) = (2, 5)$

Which corresponds to option A.