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2 years ago

Simplify: 4u + 9u Stuck on this need help

Mathematics

2 answers:

Helen [10]2 years ago

7 0

Answer:

13u

Step-by-step explanation:

These are like terms so you may combine them

4u+9u=13u

IrinaVladis [17]2 years ago

3 0

Answer:

they have the same variable, so we just add them together.

$4u + 9u = 13u$

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The line segment between (9,6) and (-2,-1) is bisected at (3.5,2.5). Find the y-intercept of the perpendicular bisector.

tangare [24]

Answer:

Y-intercept is (0,8)

Step-by-step explanation:

Firstly, we need to get the equation of the line segment

We have the general equation as;

y = mx + b

m is the slope and b is the y-intercept

So for the slope between (9,6) and (-2,-1); we have

m = (y2-y1)/(x2-x1)

m = (-1-6)/(-2-9) = -7/-11 = 7/11

Mathematically, when two lines are perpendicular, their slopes have a product of -1

Let the slope of the second line be m

m * 7/11 = -1

7m = -11

m = -11/7

The equation of the second line is;

y = mx + b

y = -11x/7 + b

The line passes through the point (3.5,2.5)

So,

2.5 = -11/7(3.5) + b

2.5 = -5.5 + b

b = 2.5 + 5.5

b = 8

so the y-intercept of the perpendicular bisector is 8

4 0

2 years ago

Simplify the complex numbers using de Moivre's Theorem and match them with their solutions.

alexandr1967 [171]

For the numbers in $a+bi$ form, convert to polar form:

$1+i=\sqrt2\dfrac{1+i}{\sqrt2}=\sqrt2\left(\cos\dfrac\pi4+i\sin\dfrac\pi4\right)$

By DeMoivre's theorem,

$(1+i)^5=(\sqrt2)^5\left(\cos\dfrac{5\pi}4+i\sin\dfrac{5\pi}4\right)=4\sqrt2\dfrac{-1-i}{\sqrt2}=-4-4i$

$-1+i=\sqrt2\dfrac{-1+i}{\sqrt2}=\sqrt2\left(\cos\dfrac{3\pi}4+i\sin\dfrac{3\pi}4}\right)$

$\implies(-1+i)^6=(\sqrt2)^6\left(\cos\dfrac{18\pi}4+i\sin\dfrac{18\pi}4\right)=8i$

$\sqrt3+i=2\dfrac{\sqrt3+i}2=2\left(\cos\dfrac\pi6+i\sin\dfrac\pi6\right)$

$\implies2(\sqrt3+i)^{10}=2^{11}\left(\cos\dfrac{10\pi}6+i\sin\dfrac{10\pi}6\right)=2^{11}\dfrac{1-i\sqrt3}2=2^{10}(1-i\sqrt3)$

For the numbers already in polar form, DeMoivre's theorem can be applied directly:

$2\left(\cos20^\circ+i\sin20^\circ\right)^3=2\left(\cos60^\circ+i\sin60^\circ\right)=2\dfrac{1+i\sqrt3}2=1+i\sqrt3$

$2\left(\cos\dfrac\pi4+i\sin\dfrac\pi4\right)^4=2(\cos\pi+i\sin\pi)=-2$

At second glance, I think the 2s in the last two numbers should also be getting raised to the 3rd and 4th powers:

$\left(2(\cos20^\circ+i\sin20^\circ)\right)^3=8\left(\cos60^\circ+i\sin60^\circ\right)=4+4\sqrt3$

$\left(2\left(\cos\dfrac\pi4+i\sin\dfrac\pi4\right)\right)^4=16(\cos\pi+i\sin\pi)=-16$

4 0

2 years ago

What is the value of B??

Maurinko [17]

The answer is 3.75.

Since the length of 'b' is one-half that of 7.5 based on the diagram (we know this because the partial radii connecting the two lines, or chords, are the same length, meaning the two chords are equal);

7.5 ⇒ 3.75
 2

Hope that helps.

7 0

3 years ago

Solve for c in the equation 32c = 128.

pishuonlain [190]

Answer

A. c = 4

Explanation

In algebra, what you do to one side of the equation, the same has to be done on the other side.

32c = 128

divide both sides by 32

32c = 128.

32c ÷ 32 = 128 ÷ 32

c = 128/32

= 4

7 0

3 years ago

Change 17/25 to thousandths ....... need help with that problem

Evgesh-ka [11]

The answer i came up with is 0.68 i don't know if thats what you need or not. hopefully i helped.

8 0

3 years ago