II. f(x) doubles for each increase of 1 in the x values. Thus, r must be 2, and so we our ar^1 = 6 from ( I ) above becomes f(x) = a*2^x. Applying the restriction ar^1 = 6 results in f(1) = a*2^1 = 6, or a = 3.
Then f(x) = ar^x becomes f(x) = 3*2^2 (Answer A)
Answer: 16
Step-by-step explanation:
For a perfect square each factor is identical.
Now, we have to find a number that adds to get 8.
The only option is (x+4)(x+4). When you distribute, you get x²+8x+16.
Now, we know that the missing number is 16.
Answer:
Q1 --> 18.5
The correct answer with step-by-step explanation:
