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shepuryov [24]
3 years ago
11

3 over 4 open parentheses 1 half x space minus space 12 close parentheses space plus space 4 over 5

Mathematics
1 answer:
lesantik [10]3 years ago
4 0

For this case we have the following expression:

\frac {3} {4} (\frac {1} {2} x-12) + \frac {4} {5}

Rewriting the expression we have:

We apply distributive property to the terms of parentheses:

\frac {3} {8} x- \frac {36} {4} + \frac {4} {5}\\\frac {3} {8} x-9 + \frac {4} {5}\\\frac {3} {8} x- \frac {41} {5}\\

Answer:

\frac {3} {8} x- \frac {41} {5}

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Answer:

A

Step-by-step explanation:

Using the sine ratio in the right triangle

sin40° = \frac{opposite}{hypotenuse} = \frac{AC}{AB} = \frac{AC}{7}

Multiply both sides by 7, thus

AC = 7sin40° → A

4 0
3 years ago
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Mei and Alberto are selling cookie dough. Mei sold 11 packages of chocolate chip and 12 packages of gingerbread for a total of $
ycow [4]

Answer:

The price of a package of chocolate chip is $13.25

The price of a package of gingerbread is $17.18

Step-by-step explanation:

11x + 12y = 352

10x +8y = 270

Let "x" be the price of a package of chocolate chip.

Let "y" be the price of a package of gingerbread.

11x + 12y = 352(Multiply the 1st row by 10)

10x +8y = 270 (Multiply the 2nd row by 11)

-------------------

110x + 120y = 3520

110x +88y = 2970

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y =550/3

y = 17.1875

The price of a package of gingerbread "y" is $17.18

Let's pick the first equation "110x + 120y = 3520"

110x + 120y = 3520

110x+ 120(17.1875)= 3520

110x+2062.5=3520

110x=3520−2062.5

110x=1457.5

x= 1457.5/110

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The price of a package of chocolate chip is $13.25

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3 years ago
From a group of 12 students, we want to select a random sample of 4 students to serve on a university committee. How many combin
borishaifa [10]

Answer:

495 combinations of 4 students can be selected.

Step-by-step explanation:

The order of the students in the sample is not important. So we use the combinations formula to solve this question.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

How many combination of random samples of 4 students can be selected?

4 from a set of 12. So

C_{n,x} = \frac{12!}{4!(8)!} = 495

495 combinations of 4 students can be selected.

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Answer:

a: vertical stretch

h: horizontal translation (remember not to get signs mixed up!)

k: vertical translation

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