Answer: 278.30 pounds (if the gasoline does not contain ethanol)
317.12 pounds (if the gasoline does contain ethanol)
Step-by-step explanation:
If the truck averages 12 miles per gallon, then in 170 miles it consumes:
170mi/12mi = 14.17 gallons.
We know that for one gallon consumed, the carbon dioxide emitted into the atmosphere is 19.64 pounds. (assuming it does not contain ethanol)
Then for 14.17 gallons consumed, we have a emission of:
14.17*19.64 pounds = 278.30 pounds
I the gasoline contains ethanlol, for a gallon the emiision is around 22.38 pounds.
In this case the total emission is:
14.17*22.38 pounds = 317.12 pounds
It does not crosses any axises. 3rd case is true. I passes through the point 1, e
9*724 answer is 6516. . . . . . . . .
(2+2i)(5+3i)
10+6i+10i+6i^2
10+16i+6(-1)
4+16i
When you have an “i^2”, you also have a negative one. The simplified answer is 4+16i
