What are the first three terms of the sequence a1 = 3 and an = 2(an-1)^2? I thought the answer was 3,18,32 but that's not an opt

Question

3 years ago

14

ion! help????

2 answers:

Sloan [31] · Answer 1 · 2022-06-09T03:16:15+03:00

Sloan [31]3 years ago

4 0

Answer:

3,18,648

Step-by-step explanation:

We are asked to find out the first three terms of the sequence.

Recurring formula is given as

$a_{n} =2(a_{n-1} ^2)$

Since I term = 3

$a_{2} =2(a_{1})^2=2(3^2)=18$

Applying the same rule,

third term

= $a_{3} =2(a_{2})^2\\=2(18^2)\\=648$

Like this we can find out any number of terms using this recursive formula

7nadin3 [17] · Answer 2 · 2022-06-09T01:52:47+03:00

3 0

A1=3
a2=2(3^2)=18
a3=2(18^2)=648